本文实例讲述了PHP日期函数date格式化UNIX时间的方法。分享给大家供大家参考。具体分析如下：
日期函数可以根据指定的格式将一个unix时间格式化成想要的文本输出
使用到函数语法如下
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string date (string $Format);string date (string $Format, int $Time); |
下面是演示代码
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<?phpecho "When this page was loaded,\n";echo 'It was then ', date ('r'), "\n";echo 'The currend date was ', date ('F j, Y'), "\n";echo 'The currend date was ', date ('M j, Y'), "\n";echo 'The currend date was ', date ('m/d/y'), "\n";echo 'The currend date was the ', date ('jS \o\f M, Y'), "\n";echo 'The currend time was ', date ('g:i:s A T'), "\n";echo 'The currend time was ', date ('H:i:s O'), "\n";echo date ('Y');date ('L')?(print ' is'):(print ' is not');echo " a leap year\n";echo time ('U'), " seconds had elapsed since January 1, 1970.\n";?> |
输出结果如下
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It was then Sat, 26 Dec 2009 07:09:51 +0000The currend date was December 26, 2009The currend date was Dec 26, 2009The currend date was 12/26/09The currend date was the 26th of Dec, 2009The currend time was 7:09:51 AM GMTThe currend time was 07:09:51 +00002009 is not a leap year1261811391 seconds had elapsed since January 1, 1970. |
希望本文所述对大家的php程序设计有所帮助。
