本文实例讲述了Python正则表达式实现截取成对括号的方法。分享给大家供大家参考，具体如下：
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strs = '1(2(3(4(5(67)6)7)8)9)0'reg1 = re.compile('([()])∗') #一对括号reg2 = re.compile('([()]|\([()]∗)*\)') #两对括号reg3 = re.compile('([()]|\([()]∗|([()]|\([()]∗)*\))*\)') #三层 |
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#匹配成对括号正则表达式def getReg(self, count, bracket = '()'): leftBracket = bracket[0] rightBracket = bracket[1] count -= 1 regBasic = leftBracket + '(?:[^' + leftBracket + rightBracket + '])*' + rightBracket if count < 0: regBasic = '' if count > 0: for i in xrange(count): tempNum = regBasic.rfind('*') - 1 regBasic = regBasic[:tempNum] + "|" + regBasic + regBasic[tempNum:] return regBasic |
希望本文所述对大家Python程序设计有所帮助。
