本文实例讲述了PHP响应post请求上传文件的方法。分享给大家供大家参考，具体如下：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
|
function send_file($url, $post = '', $file = '') { $eol = "\r\n"; $mime_boundary = md5 ( time () ); $data = ''; $confirmation = ''; date_default_timezone_set ( "Asia/Shanghai" ); $time = date ( "Y-m-d H:i:s " ); $post ["filename"] = $file [filename]; foreach ( $post as $key => $value ) { $data .= '--' . $mime_boundary . $eol; $data .= 'Content-Disposition: form-data; '; $data .= "name=" . $key . $eol . $eol; $data .= $value . $eol; } $data .= '--' . $mime_boundary . $eol; $data .= 'Content-Disposition: form-data; name=' . $file [name] . '; filename=' . $file [filename] . $eol; $data .= 'Content-Type: text/plain' . $eol; $data .= 'Content-Transfer-Encoding: binary' . $eol . $eol; $data .= $file [filedata] . $eol; $data .= "--" . $mime_boundary . "--" . $eol . $eol; $params = array ('http' => array ('method' => 'POST', 'header' => 'Content-Type: multipart/form-data;boundary=' . $mime_boundary . $eol, 'content' => $data ) ); $ctx = stream_context_create ( $params ); $response = file_get_contents ( $url, FILE_TEXT, $ctx ); return $response;} |
希望本文所述对大家PHP程序设计有所帮助。
