本文实例讲述了Python实现嵌套列表及字典并按某一元素去重复功能。分享给大家供大家参考，具体如下：
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#! /usr/bin/env python#coding=utf-8class HostScheduler(object): def __init__(self, resource_list): self.resource_list = resource_list def MergeHost(self): allResource=[] allResource.append(self.resource_list[0]) for dict in self.resource_list: #print len(l4) k=0 for item in allResource: #print 'item' if dict['host'] != item['host']: k=k+1 #continue else: break if k == len(allResource): allResource.append(dict) taskhost=[] for item in allResource: taskhost.append(item['host']) return taskhost#该函数实现嵌套列表中，按某一元素去重复def deleteRepeat(): #1、列表中嵌套列表。按元素‘b'实现去重复 l1=[['b',1],['b',2],['c',3],['a',1],['b',1],['b',1],] l2=[] l2.append(l1[0]) for data in l1: #print len(l2) k=0 for item in l2: #print 'item' if data[0] != item[0]: k=k+1 else: break if k == len(l2): l2.append(data) print "l2: ",l2 #2、列表中嵌套字典。按键值host实现去重复 l3=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2}, {'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2}, {'host':'compute24', 'cpu':2}] l4=[] l4.append(l3[0]) for dict in l3: #print len(l4) k=0 for item in l4: #print 'item' if dict['host'] != item['host']: k=k+1 #continue else: break if k == len(l4): l4.append(dict) print "l4: ",l4if __name__ == '__main__': #deleteRepeat() resource_list=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2}, {'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2}, {'host':'compute24', 'cpu':2}] hostSchedule=HostScheduler(resource_list) taskhost=hostSchedule.MergeHost() print '服务器之家测试结果: ' print 'taskhost: ' print taskhost |
运行结果：
希望本文所述对大家Python程序设计有所帮助。
原文链接：http://blog.csdn.net/will130/article/details/50441937
