|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
|
#include<stdio.h>int main(){ int sz[10]={0},zm[26]={0},z[26]={0},i,space=0,e=0,t=0; char c; printf("请输入一段字符，统计其中各字符的数量\n"); while((c=getchar())!='\n') { if(c<='z'&&c>='a') zm[c-'a']++; else if(c<='Z'&&c>='A') z[c-'A']++; else if(c<='9'&&c>='0') sz[c-'0']++; else if(c==' ') space++; else e++; } printf("\n\n"); for(i=0;i<=9;i++) { t++; printf(" %d的个数为%d ",i,sz[i]); if(t%3==0) printf("\n"); } t=0; printf("\n\n\n"); for(i=0;i<=25;i++) { t++; printf(" %c的个数为%d ",i+97,zm[i]); if(t%3==0) printf("\n"); } t=0; printf("\n\n\n"); for(i=0;i<=25;i++) { t++; printf(" %c的个数为%d ",i+65,z[i]); if(t%3==0) printf("\n"); } t=0; printf("\n\n\n"); printf(" 空格的个数为%d\n\n",space); printf(" 其他字符的个数为%d\n",e); return 0;} |
再来一则C语言统计输入字符个数的代码
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
|
#include <stdio.h>#define MAXWORD 30 //单词的最大长度#define IN 1 //在单词内，即没有遇到空格#define OUT 0 //在单词外，即遇到了空格/*word length ==> wl单词长度简称*/int wl(){ char c; int i; int nc; int state; //state为单词的状态：IN或OUT; int overflow; //操过MAXWORD的单词个数 int wl[MAXWORD]; //长度为1~30的的字符长度统计 state = OUT; nc = 0; overflow = 0; for(i = 1; i < MAXWORD; ++i) wl[i] = 0; while((c = getchar()) != EOF) if(c == ' ' || c == '\n' || c == '\t') { state = OUT; if(nc > 0) if(nc < MAXWORD) ++wl[nc]; else ++overflow; nc = 0; } else if(state == OUT) { state = IN; nc = 1; } else ++nc; for(i = 1; i < MAXWORD; ++i) printf("长度为：%d的单词个数为：%d : \n\n", i, wl[i]); return 0;}main(){ wl();} |
以上所述就是本文的全部内容了，希望大家能够喜欢
