本文实例讲述了php正则判断是否为合法身份证号的方法。分享给大家供大家参考，具体如下：
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/** * 判断是否为合法的身份证号码 * @param $mobile * @return int */function isCreditNo($vStr){ $vCity = array( '11','12','13','14','15','21','22', '23','31','32','33','34','35','36', '37','41','42','43','44','45','46', '50','51','52','53','54','61','62', '63','64','65','71','81','82','91' ); if (!preg_match('/^([\d]{17}[xX\d]|[\d]{15})$/', $vStr)) return false; if (!in_array(substr($vStr, 0, 2), $vCity)) return false; $vStr = preg_replace('/[xX]$/i', 'a', $vStr); $vLength = strlen($vStr); if ($vLength == 18) { $vBirthday = substr($vStr, 6, 4) . '-' . substr($vStr, 10, 2) . '-' . substr($vStr, 12, 2); } else { $vBirthday = '19' . substr($vStr, 6, 2) . '-' . substr($vStr, 8, 2) . '-' . substr($vStr, 10, 2); } if (date('Y-m-d', strtotime($vBirthday)) != $vBirthday) return false; if ($vLength == 18) { $vSum = 0; for ($i = 17 ; $i >= 0 ; $i--) { $vSubStr = substr($vStr, 17 - $i, 1); $vSum += (pow(2, $i) % 11) * (($vSubStr == 'a') ? 10 : intval($vSubStr , 11)); } if($vSum % 11 != 1) return false; } return true;} |
希望本文所述对大家PHP程序设计有所帮助。
