本文实例为大家分享了python使用正则筛选信用卡的具体代码，供大家参考，具体内容如下
本文来源于两个简单的题目：
1.判断一对单词是否是" anagrams "
2.判断信用卡是否合理
判断 anagramsstrong>
anagrams 的百度翻译：由颠倒字母顺序而构成的字（短语）
而题目给出例子：
[ dog , odg ]
[ dog , dog ]
[ dog , god ]
[ dog , gdo ]
均为 anagrams 。
那思路就简单了，直接拆分字母，排序，比较就 ok 。
判断信用卡
题目给出的要求如下：
the criteria are:
• it must start with a 4,5 or 6
• it must be exactly 16 digits
• it must be numbers only
• it can have a digits in groups of 4, separated by one hyphen “-“
• it should not contain any other characters.
• it must not have any 4 repeated digits.
样例输出如下：
378282246310005 invalid
30569309025904 invalid
6011111111111117 invalid
5123-2332-3232-3213 valid
py文件
两个题目合并在一个 py 文件中。
而入参数分别是两个文件的名字，一个是 anagram.txt ，另一个是 credit_cards.txt ，他们分别长这样：
最后的程序长这样：
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#! /usr/bin/python3import re#################################you need to implet the following methods:####question 1##anagram_validator() ####question 2##credit_card_validator() #################################################################################### question 1: check for anagrams:####################################################def get_list(src_str): sub_list=[] word_tmp='' for word in src_str: if word != ',': word_tmp = word_tmp+word else: sub_list.append(word_tmp) word_tmp = '' return sub_listdef read_anagram(file_name): ''' input: a file name return: a nested list of two words list example : [[word1,word2],[word3,word4]...etc] ''' with open(file_name,encoding = 'utf-8') as f: return_list =[] file_conment = f.read() file_conment_new = re.sub(r'\n',',',file_conment) file_conment_new = file_conment_new+',' subs_list = get_list(file_conment_new) i=0 while i < (len(subs_list)-1): return_list.append([subs_list[i],subs_list[i+1]]) i=i+2 return return_listdef anagram_validator(anagram): ''' input is the output from "read_anagram()". return: list of "anagrams" or "not anagrams" values for each two words example input (dog,gdo),(try,elm) then output would be ["anagrams","not anagrams"] with sequence of the input ''' result_list=[] for i in range(len(anagram)): word_font = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][0]))) word_back = ''.join((lambda x:(x.sort(),x)[1])(list(anagram[i][1]))) if word_font == word_back: result_list.append('anagrams') else: result_list.append('not anagrams') return result_list############################################# question 2: validate credit cards #############################################def read_credit_cards(file_name): ''' input: a file name return tuple of numbers ''' with open(file_name,encoding='utf-8') as f: card_conment = f.read() card_conment = re.sub(r'\[','',card_conment) card_conment = re.sub(r'\]','',card_conment) card_conment = card_conment+',' card_list = get_list(card_conment) return tuple(card_list)def credit_card_validator(numbers): ''' input: tuple of numbers return:dictionary of credit card numbers where key is the number and value if valid or invalid ''' validator_list=[] credit_dict={} for i in range(len(numbers)): validator_list.append(numbers[i]) for i in range(len(numbers)): ch_num = 0 repeat_flag = 0 for ch in validator_list[i]: if ord("a")<=ord(ch)<=ord("z"): ch_num+=1 break tmp_list = [] tmp_list = (re.sub(r"[^\d]", "", validator_list[i])) for index in range(len(tmp_list)-4): if(tmp_list[index] == tmp_list[index+1] and tmp_list[index] == tmp_list[index+2] and tmp_list[index] == tmp_list[index+3] ): repeat_flag = 1 break; if(validator_list[i][0] != '4' and validator_list[i][0] != '5' and validator_list[i][0] != '6' ): credit_dict[validator_list[i]]='invalid' elif( len(re.sub(r"\d", "", validator_list[i])) != 16 ): credit_dict[validator_list[i]]='invalid' elif(ch_num > 0): credit_dict[validator_list[i]]='invalid' elif( (re.search(r"-",validator_list[i])) and ( validator_list[i][4] != '-' or validator_list[i][9] != '-'or validator_list[i][14] != '-' ) ): credit_dict[validator_list[i]]='invalid' elif(re.search(r"[^-\d]",validator_list[i])): credit_dict[validator_list[i]]='invalid' elif(repeat_flag == 1 ): credit_dict[validator_list[i]]='invalid' else : credit_dict[validator_list[i]]='valid' space_str = '' return credit_dictdef print_credit_card_summary(dict_o): ''' input: dict return: printing summary of validation result - space between credit card and status is 40 width example: 378282246310005 invalid 30569309025904 invalid ''' space_str = '' for key in dict_o: new_str = key + dict_o[key] if(dict_o[key] == "valid"): new_str_tmp = new_str[:-5] space_lenth = 46-len(new_str) for x in range(space_lenth): space_str +=' ' print(new_str_tmp + space_str + 'valid') space_str='' else : new_str_tmp = new_str[:-7] space_lenth = 48-len(new_str) for x in range(space_lenth): space_str +=' ' print(new_str_tmp + space_str + 'invalid') space_str='' ####### the code below is for testing################################## do not change #########################import sysif __name__ == '__main__': # take care of the console inputs if len(sys.argv) <= 1: sys.argv = ['', "anagram.txt", "credit_cards.txt"] stars = '*' * 40 print(stars) print("testing question 1 --- anagrams?") print(stars) # testing reading_anagrams try: anagram = read_anagram(sys.argv[1]) if not anagram: print("read_anagram() returns none.") else: print("anagram: ", anagram) print() except exception as e: print("error (readnumbers()): ", e) # testing anagram_validator anagrams = 0 nanagrams = 0 try: if not anagram: # question 1 has not been implemented print("anagram_validator() skipped....") else: result = anagram_validator(anagram) if result == none: print("anagram_validator() returns none.") else: for i in result: if i == "anagrams": anagrams += 1 elif i == "not anagrams": nanagrams += 1 print("number of valid anagrams is {} and not anagrams is {}.".format(anagrams, nanagrams)) except exception as e: print("error (anagram_validator()):", e) # testing question 2 print("\n\n" + stars) print("testing question 2 --- credit card validator") print(stars) # testing reading_credit_cards try: tup = read_credit_cards(sys.argv[2]) if not tup: print("read_credit_cards() returns none.") else: print("the tuple of credit_cards: {}".format(tup)) except exception as e: print("error (read_credit_cards()):", e) # testing credit_card_validator vcc = 0 ivcc = 0 try: if not tup: # readin_question 2 has not been implemented print("credit_card_validator() skipped...") else: cc_dict = credit_card_validator(tup) tmp_cc_dict = cc_dict if not cc_dict: print("credit_card_validator() returns none.") else: for items in cc_dict.keys(): if cc_dict[items] == "valid": vcc += 1 elif cc_dict[items] == "invalid": ivcc += 1 print("number of valid credit cards is {} and invalid {}.".format(vcc, ivcc)) except exception as e: print("error (credit_card_validator()):", e) # testing question 2 print("\n\n" + stars) print("testing question 2b --- print credit card summary") print(stars) # testing print_credit_card_summary try: if not tmp_cc_dict: # dict credit card output has not been implemented print("print_credit_card_summary() skipped...") else: import io # do not delete this line from contextlib import redirect_stdout # do not delete this line f = io.stringio() with redirect_stdout(f): print_credit_card_summary(tmp_cc_dict) out = f.getvalue() if not out: print("print_credit_card_summary() returns none.") else: count44 = 0 count46 = 0 for line in out.splitlines(): if len(line) - len(line.split()) == 44: count44 += 1 elif len(line) - len(line.split()) == 46: count46 += 1 if count44 == vcc and count46 == ivcc: print("your format looks good") else: print("you might have some issues in your summary format") except exception as e: print("error (print_credit_card_summary()):", e) |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/qq_30650153/article/details/84110948
