本文实例讲述了php检测mysql表是否存在的方法。分享给大家供大家参考，具体如下：
pdo:
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<?php$dsn = 'mysql:dbname=test;host=127.0.0.1';$user = 'root';$password = '';try { $pdo = new PDO($dsn, $user, $password);} catch (PDOException $e) { die("数据库连接失败".$e->getMessage());}$table = 'cy_news';//判断表是否存在$result = $pdo->query("SHOW TABLES LIKE '". $table."'");$row = $result->fetchAll();if('1' == count($row)){ echo "Table exists";} else { echo "Table does not exist";}?> |
mysql:
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<?php$con = mysql_connect("localhost","root","");mysql_select_db("php_cms", $con);$table = 'cy_news';if(mysql_num_rows(mysql_query("SHOW TABLES LIKE '". $table."'"))==1) { echo "Table exists";} else { echo "Table does not exist";}?> |
希望本文所述对大家PHP程序设计有所帮助。
