大体思路
如果发总金额为 m的 n 个红包，先用一个长度为 n的临时数组 a 存放 n个随机双精度小数
，然后用 sum表示数组 a 的和，每个红包的金额
代码
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import java.util.Arrays;import java.util.Random;import java.math.*;import java.util.Scanner;public class Main { public static long now_time; public static long seed; public static int[] get_red_packets(int money, int num) { Random random = new Random(seed); seed = random.nextLong(); int[] res = new int[num]; double[] temp=new double[num]; double sum = 0; int sum2 = 0; for (int i = 0; i < num; i++) { temp[i] = random.nextDouble(); sum += temp[i]; } for (int i = 0; i < num; i++) { res[i] = 1+ (int)(temp[i] / sum * (money-num)); sum2 += res[i]-1; } res[random.nextInt(num)]+=money-sum2-num; return res; } public static void show(int[] red_packet){ System.out.println("红包 : " + Arrays.toString(red_packet)); } public static void main(String[] args) { int num, money; Scanner scanner = new Scanner(System.in); now_time = System.currentTimeMillis(); Random init_random = new Random(now_time); seed = init_random.nextLong(); System.out.println("请输入要分发的红包数量:"); num = scanner.nextInt(); System.out.println("请输入要分发的红包总金额(分):"); money = scanner.nextInt(); int a[] = get_red_packets(money,num); show(a); }} |
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原文链接：https://blog.csdn.net/Evrse/article/details/110144412
