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使用 python 实现单人AI 扫雷游戏

时间:2021-12-17 00:04     来源/作者:海拥

ai玩扫雷

很高兴又见面了!

扫雷是一款单人益智游戏,相信大部分人都在以前上微机课的时候玩过。游戏的目标是借助每个区域中相邻地雷数量的线索,清除包含隐藏的“地雷”或炸弹的单元格,但不引爆其中任何一个,全部清除后即可获胜。今天我们用 python 完成这个小程序,并且用ai来学习并实现它。

看看我们将要实现的最终样子。

使用 python 实现单人AI 扫雷游戏

运行扫雷

1.确保安装了python 3.6+。
2.安装pygame。
3.克隆这个存储库:

github地址:https://github.com/wanghao221/minesweeper

设置 minesweeper.py 

扫雷游戏表示

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class minesweeper():
 
def __init__(self, height=8, width=8, mines=8):
    
    # 设置初始宽度、高度和地雷数量   
    self.height = height
    self.width = width
    self.mines = set()
 
    # 初始化一个没有地雷的空字段   
    self.board = []   
    for i in range(self.height):
        row = []       
        for j in range(self.width):
            row.append(false)
        self.board.append(row)
 
    # 随机添加地雷   
    while len(self.mines) != mines:       
        i = random.randrange(height)
        j = random.randrange(width)       
        if not self.board[i][j]:
            self.mines.add((i, j))
            self.board[i][j] = true
 
    # 最开始,玩家没有发现地雷   
    self.mines_found = set()

输出地雷所在位置的基于文本的表示

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def print(self):
for i in range(self.height):
        print("--" * self.width + "-")
        
        for j in range(self.width):
            
            if self.board[i][j]:
                print("|x", end="")
            
            else:
                print("| ", end="")
        print("|")
    
    print("--" * self.width + "-")
 
 
def is_mine(self, cell):
    i, j = cell
    return self.board[i][j]
 
def nearby_mines(self, cell):

返回给定单元格的一行和一列内的地雷数,不包括单元格本身。

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def nearby_mines(self, cell):
 
        # 保持附近地雷的数量
        count = 0
 
        # 遍历一行和一列内的所有单元格
        for i in range(cell[0] - 1, cell[0] + 2):
            for j in range(cell[1] - 1, cell[1] + 2):
 
                # 忽略单元格本身
                if (i, j) == cell:
                    continue
 
                # 如果单元格在边界内并且是地雷,则更新计数
                if 0 <= i < self.height and 0 <= j < self.width:
                    if self.board[i][j]:
                        count += 1
        return count

检查是否已标记所有地雷。

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def won(self):
        return self.mines_found == self.mines

关于扫雷游戏的逻辑语句
一个句子由一组棋盘单元和这些单元格的数量组成。

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class sentence():
    def __init__(self, cells, count):
        self.cells = set(cells)
        self.count = count
 
    def __eq__(self, other):
        return self.cells == other.cells and self.count == other.count
 
    def __str__(self):
        return f"{self.cells} = {self.count}"
 
    def known_mines(self):

返回 self.cells 中已知为地雷的所有单元格的集合。

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def known_mines(self): 
    if len(self.cells) == self.count:
        return self.cells

返回 self.cells 中已知安全的所有单元格的集合。

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def known_safes(self):     
    if self.count == 0:
        return self.cells

鉴于已知单元格是地雷,更新内部知识表示。

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def mark_mine(self, cell):      
    if cell in self.cells:
        self.cells.discard(cell)
        self.count -= 1

鉴于已知单元格是安全的,更新内部知识表示。

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def mark_safe(self, cell): 
        if cell in self.cells:
            self.cells.discard(cell)

扫雷游戏玩家

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class minesweeperai():
    def __init__(self, height=8, width=8):
        # 设置初始高度和宽度       
        self.height = height
        self.width = width
        # 跟踪点击了哪些单元格
        self.moves_made = set()
        # 跟踪已知安全或地雷的细胞       
        self.mines = set()
        self.safes = set()
        # 关于已知为真游戏的句子列表
        self.knowledge = []

将一个单元格标记为地雷,并更新所有知识以将该单元格也标记为地雷。

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def mark_mine(self, cell):
       self.mines.add(cell)
       
       for sentence in self.knowledge:
           sentence.mark_mine(cell)

将一个单元格标记为安全,并更新所有知识以将该单元格也标记为安全。

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def mark_safe(self, cell): 
    self.safes.add(cell)       
        for sentence in self.knowledge:
            sentence.mark_safe(cell)

用于获取所有附近的单元格

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def nearby_cells(self, cell):
    cells = set()
    
            for i in range(cell[0] - 1, cell[0] + 2):
                for j in range(cell[1] - 1, cell[1] + 2):
    
                    if (i, j) == cell:
                        continue
    
                    if 0 <= i < self.height and 0 <= j < self.width:
                        cells.add((i, j))
    
            return cells

当扫雷板告诉我们,对于给定的安全单元,有多少相邻单元中有地雷时调用。
这个功能应该:
1)将单元格标记为已进行的移动
2)将单元格标记为安全
3)根据 cellcount 的值在 ai 的知识库中添加一个新句子
4)如果可以根据 ai 的知识库得出结论,则将任何其他单元格标记为安全或地雷
5) 如果可以从现有知识中推断出任何新句子,则将其添加到 ai 的知识库中

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def add_knowledge(self, cell, count):
        self.moves_made.add(cell)
 
        # 标记单元格安全
 
        if cell not in self.safes:   
            self.mark_safe(cell)
                    
        # 获取所有附近的单元格
 
        nearby = self.nearby_cells(cell)      
        nearby -= self.safes | self.moves_made    
        new_sentence = sentence(nearby, count)
        self.knowledge.append(new_sentence)
 
        new_safes = set()
        new_mines = set()
 
        for sentence in self.knowledge:
            
            if len(sentence.cells) == 0:
                self.knowledge.remove(sentence)          
            else:
                tmp_new_safes = sentence.known_safes()
                tmp_new_mines = sentence.known_mines()               
                if type(tmp_new_safes) is set:
                    new_safes |= tmp_new_safes
                
                if type(tmp_new_mines) is set:
                    new_mines |= tmp_new_mines       
        for safe in new_safes:
            self.mark_safe(safe)       
        for mine in new_mines:
            self.mark_mine(mine)
        prev_sentence = new_sentence
        new_inferences = []
        for sentence in self.knowledge:
            if len(sentence.cells) == 0:
                self.knowledge.remove(sentence)
            elif prev_sentence == sentence:
                break
            elif prev_sentence.cells <= sentence.cells:
                inf_cells = sentence.cells - prev_sentence.cells
                inf_count = sentence.count - prev_sentence.count
                new_inferences.append(sentence(inf_cells, inf_count))
            prev_sentence = sentence
        self.knowledge += new_inferences
    def make_safe_move(self):

返回一个安全的单元格以在扫雷板上选择。必须知道该移动是安全的,而不是已经做出的移动。
该函数可以使用 self.mines、self.safes 和 self.moves_made 中的知识,但不应修改任何这些值。

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def make_safe_move(self):
    safe_moves = self.safes.copy()
    safe_moves -= self.moves_made
    if len(safe_moves) == 0:
    return none
    return safe_moves.pop()
    def make_random_move(self):

返回在扫雷板上进行的移动。应该在以下单元格中随机选择:
1) 尚未被选中
2) 不知道是地雷

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def make_random_move(self):
    if len(self.moves_made) == 56:
        return none
    
    random_move = random.randrange(self.height), random.randrange(self.height)
    
    not_safe_moves = self.moves_made | self.mines
    
    while random_move in not_safe_moves:
        random_move = random.randrange(self.height), random.randrange(self.height)
    
    return random_move

使用 python 实现单人AI 扫雷游戏

设置 runner.py 运行程序

颜色

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black = (0, 0, 0)
gray = (180, 180, 180)
white = (255, 255, 255)

创建游戏

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pygame.init()
size = width, height = 600, 400
screen = pygame.display.set_mode(size)

字体

字体可以在自己电脑中c:\windows\fonts的位置选择自己喜欢的复制到项目中 assets/fonts目录下即可,我用的是楷体

使用 python 实现单人AI 扫雷游戏

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open_sans = "assets/fonts/simkai.ttf"
smallfont = pygame.font.font(open_sans, 20)
mediumfont = pygame.font.font(open_sans, 28)
largefont = pygame.font.font(open_sans, 40)

计算面板尺寸

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board_padding = 20
board_width = ((2 / 3) * width) - (board_padding * 2)
board_height = height - (board_padding * 2)
cell_size = int(min(board_width / width, board_height / height))
board_origin = (board_padding, board_padding)

添加图片
这里我们只用了两张图,一个是地雷,一个是用来标记地雷的旗帜

使用 python 实现单人AI 扫雷游戏使用 python 实现单人AI 扫雷游戏

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flag = pygame.image.load("assets/images/flag.png")
flag = pygame.transform.scale(flag, (cell_size, cell_size))
mine = pygame.image.load("assets/images/mine.png")
mine = pygame.transform.scale(mine, (cell_size, cell_size))

创建游戏和 ai 代理

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game = minesweeper(height=height, width=width, mines=mines)
ai = minesweeperai(height=height, width=width)

跟踪显示的单元格、标记的单元格以及是否被地雷击中

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revealed = set()
flags = set()
lost = false

最初显示游戏说明

使用 python 实现单人AI 扫雷游戏

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instructions = true
 
while true:
 
    # 检查游戏是否退出
    for event in pygame.event.get():
        if event.type == pygame.quit:
            sys.exit()
 
    screen.fill(black)
 
    # 显示游戏说明
 
    if instructions:
 
        # 标题
        title = largefont.render("海拥 | 扫雷", true, white)
        titlerect = title.get_rect()
        titlerect.center = ((width / 2), 50)
        screen.blit(title, titlerect)
 
        # rules
        rules = [
            "单击一个单元格以显示它",
            "右键单击一个单元格以将其标记为地雷",
            "成功标记所有地雷以获胜!"
        ]
        for i, rule in enumerate(rules):
            line = smallfont.render(rule, true, white)
            linerect = line.get_rect()
            linerect.center = ((width / 2), 150 + 30 * i)
            screen.blit(line, linerect)
 
        # 开始游戏按钮
        
        buttonrect = pygame.rect((width / 4), (3 / 4) * height, width / 2, 50)
        buttontext = mediumfont.render("开始游戏", true, black)
        buttontextrect = buttontext.get_rect()
        buttontextrect.center = buttonrect.center
        pygame.draw.rect(screen, white, buttonrect)
        screen.blit(buttontext, buttontextrect)
 
        # 检查是否点击播放按钮
        
        click, _, _ = pygame.mouse.get_pressed()
        if click == 1:
            mouse = pygame.mouse.get_pos()
            if buttonrect.collidepoint(mouse):
                instructions = false
                time.sleep(0.3)
 
        pygame.display.flip()
        continue

画板

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cells = []
for i in range(height):
    row = []
    for j in range(width):
 
        # 为单元格绘制矩形
        
        rect = pygame.rect(
            board_origin[0] + j * cell_size,
            board_origin[1] + i * cell_size,
            cell_size, cell_size
        )
        pygame.draw.rect(screen, gray, rect)
        pygame.draw.rect(screen, white, rect, 3)
 
        # 如果需要,添加地雷、旗帜或数字
        
        if game.is_mine((i, j)) and lost:
            screen.blit(mine, rect)
        elif (i, j) in flags:
            screen.blit(flag, rect)
        elif (i, j) in revealed:
            neighbors = smallfont.render(
                str(game.nearby_mines((i, j))),
                true, black
            )
            neighborstextrect = neighbors.get_rect()
            neighborstextrect.center = rect.center
            screen.blit(neighbors, neighborstextrect)
 
        row.append(rect)
    cells.append(row)

ai 移动按钮

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aibutton = pygame.rect(
    (2 / 3) * width + board_padding, (1 / 3) * height - 50,
    (width / 3) - board_padding * 2, 50
)
buttontext = mediumfont.render("ai 移动", true, black)
buttonrect = buttontext.get_rect()
buttonrect.center = aibutton.center
pygame.draw.rect(screen, white, aibutton)
screen.blit(buttontext, buttonrect)

重置按钮

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resetbutton = pygame.rect(
       (2 / 3) * width + board_padding, (1 / 3) * height + 20,
       (width / 3) - board_padding * 2, 50
   )
   buttontext = mediumfont.render("重置", true, black)
   buttonrect = buttontext.get_rect()
   buttonrect.center = resetbutton.center
   pygame.draw.rect(screen, white, resetbutton)
   screen.blit(buttontext, buttonrect)

显示文字

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text = "失败" if lost else "获胜" if game.mines == flags else ""
text = mediumfont.render(text, true, white)
textrect = text.get_rect()
textrect.center = ((5 / 6) * width, (2 / 3) * height)
screen.blit(text, textrect)
 
move = none
 
left, _, right = pygame.mouse.get_pressed()

检查右键单击以切换标记

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if right == 1 and not lost:
    mouse = pygame.mouse.get_pos()
    
    for i in range(height):
        
        for j in range(width):
            
            if cells[i][j].collidepoint(mouse) and (i, j) not in revealed:
                
                if (i, j) in flags:
                    flags.remove((i, j))
                
                else:
                    flags.add((i, j))
                time.sleep(0.2)
 
elif left == 1:
    mouse = pygame.mouse.get_pos()

如果单击 ai 按钮,则进行 ai 移动

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if aibutton.collidepoint(mouse) and not lost:
        move = ai.make_safe_move()
        
        if move is none:
            move = ai.make_random_move()
            
            if move is none:
                flags = ai.mines.copy()
                print("no moves left to make.")
            
            else:
                print("no known safe moves, ai making random move.")
        
        else:
            print("ai making safe move.")
        time.sleep(0.2)

重置游戏状态

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elif resetbutton.collidepoint(mouse):
        
        game = minesweeper(height=height, width=width, mines=mines)
        ai = minesweeperai(height=height, width=width)
        revealed = set()
        flags = set()
        lost = false
        continue

用户自定义动作

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elif not lost:
        
        for i in range(height):
            
            for j in range(width):
                
                if (cells[i][j].collidepoint(mouse)
                        and (i, j) not in flags
                        and (i, j) not in revealed):
                    move = (i, j)

行动起来,更新ai知识

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if move:
    
    if game.is_mine(move):
        lost = true
    
    else:
        nearby = game.nearby_mines(move)
        revealed.add(move)
        ai.add_knowledge(move, nearby)
 
 
pygame.display.flip()

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原文链接:https://blog.csdn.net/qq_44273429/article/details/119318513

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