如下：
复制代码代码如下:
CREATE FUNCTION [dbo].[udf_DaysInMonth]
(
@Date DATETIME
)
RETURNS INT
AS
BEGIN
DECLARE @dim AS TABLE (M INT,Dy INT)
INSERT INTO @dim VALUES
(1,31),(3,31),(5,31),(7,31),(8,31),(10,31),(12,31),
(4,30),(6,30),(9,30),(11,30),
(2,
CASE WHEN (YEAR(@Date) % 4 = 0 AND YEAR(@Date) % 100 <> 0) OR (YEAR(@Date) % 400 = 0)
THEN 29
ELSE 28 END
)
DECLARE @RValue INT
SELECT @RValue = [Dy] FROM @dim WHERE [M] = MONTH(@Date)
RETURN @RValue
END
GO
获取月份天数，以前在博客上也有写过，不过它只是取得二月份的天数。链接如下：http://www.cnblogs.com/insus/articles/2025019.html
现第一眼看见专案中这个函数，总觉它写得不够好的感觉，是否能把它改写得更好些，启发点也是从获取二月份天数的CASE函数想起的。
因此，我尝试改了，如下：
复制代码代码如下:
CREATE FUNCTION [dbo].[udf_DaysInMonth]
(
@Date DATETIME
)
RETURNS INT
AS
BEGIN
RETURN CASE WHEN MONTH(@Date) IN (1,3,5,7,8,10,12) THEN 31
WHEN MONTH(@Date) IN (4,6,9,11) THEN 30
ELSE CASE WHEN (YEAR(@Date) % 4 = 0 AND YEAR(@Date) % 100 <> 0) OR (YEAR(@Date) % 400 = 0)
THEN 29
ELSE 28
END
END
END
如果你已经有引过Insus.NET那个获取二月份天数的自定义函数，也可以参考下面这个版本：
复制代码代码如下:
CREATE FUNCTION [dbo].[udf_DaysInMonth]
(
@Date DATETIME
)
RETURNS INT
AS
BEGIN
RETURN CASE WHEN MONTH(@Date) IN (1,3,5,7,8,10,12) THEN 31
WHEN MONTH(@Date) IN (4,6,9,11) THEN 30
ELSE [dbo].[DaysOfFebruary](YEAR(@Date))
END
END
