1. 计算给出两个时间之间的时间差
|
1
2
3
4
5
6
7
8
9
10
11
|
import datetime as dt# current timecur_time = dt.datetime.today()# one daypre_time = dt.date(2016, 5, 20) # eg: 2016.5.20delta = cur_time - pre_time# if you want to get discrepancy in daysprint delta.days# if you want to get discrepancy in hoursprint delta.hours# and so on |
2. 获取n天前的时间
|
1
2
3
|
cur_time = dt.now()# previous n dayspre_time = dt.timedelta(days=n) |
3. 将给定的时间精确到天或者其他单位
|
1
2
3
|
cur_time = dt.now()# get day of current timecur_day = cur_time.replace(hour=0, minute=0, second=0, mircrosecond=0) |
4. 获取一连串的时间序列（返回list）
|
1
2
|
cur_time = dt.datetime.today()datelist = [cur_time - dt.timedelta(days=x) for x in range(0, 100)] |
或者
|
1
2
|
import pandas as pddatelist = pd.date_range(pd.datetime.today(), periods=100).tolist() |
5. 将时间字符串转化为datetime类型
|
1
2
|
date_formate = "%Y-%m-%d" # year-month-daytime = dt.strptime('2016-06-22', date_format) |
6. 将时间类型转化为字符串类型
|
1
|
time_str = dt.strftime("%Y-%m-%d", dt.now()) # return like "2016-06-22" |
以上就是小编为大家带来的浅谈Python中用datetime包进行对时间的一些操作全部内容了，希望大家多多支持服务器之家~
