使用eclipse快速新建spirngboot项目的方法

分享两种eclipse创建spirngboot项目的办法：

方案一：创建maven项目后修改pom文件

1.用eclipse创建简单的maven项目

2.修改pom文件

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									<?xml version="1.0" encoding="UTF-8"?>

									<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

									  xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">

									  <modelVersion>4.0.0</modelVersion>

									  <groupId>com.chry</groupId>

									  <artifactId>studySpringBoot</artifactId>

									  <version>0.0.1-SNAPSHOT</version>

									  <properties>

									    <java.version>1.7</java.version>

									  </properties>

									  <!-- Inherit defaults from Spring Boot -->

									  <parent>

									    <groupId>org.springframework.boot</groupId>

									    <artifactId>spring-boot-starter-parent</artifactId>

									    <version>1.4.0.RELEASE</version>

									  </parent>

									  <!-- Add typical dependencies for a web application -->

									  <dependencies>

									    <dependency>

									      <groupId>org.springframework.boot</groupId>

									      <artifactId>spring-boot-starter-web</artifactId>

									    </dependency>  

									  </dependencies>

									  <!-- Package as an executable jar -->

									  <build>

									    <finalName>studySpringBoot</finalName>

									  </build>

									</project>

3.新建一个类文件

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									package com.chry.study;

									import org.springframework.boot.SpringApplication; 

									import org.springframework.boot.autoconfigure.EnableAutoConfiguration;

									import org.springframework.stereotype.Controller;

									import org.springframework.web.bind.annotation.RequestMapping;

									import org.springframework.web.bind.annotation.ResponseBody;

									@Controller

									@EnableAutoConfiguration

									public class SampleController {

									@RequestMapping("/")

									@ResponseBody

									String home() {

									     return "Hello World!";

									  }

									   public static void main(String[] args) throws Exception {

									     SpringApplication.run(SampleController.class, args);

									  }

									}