我们在开发过程中，有时候需要把float，int型等数字作为金额类型数字显示会出现很多问题，比如float会显示成 965868.4599999，int型没有小数位等各种各样的问题。我们需要进行转换显示，才能保证阅读人性化。
方法一：
这里只贴上主要代码：
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# 金额人性化def humanized_amount(self, *args, **kwargs): """ 金额人性化,保留二位小数，再进行人性化显示 compel强制二位，默认True， """ if not CheckData(self.__mark).is_int_or_float: return {"code": "0001", "msg": "必须传入数字", "data": None} else: figure = float(self.__mark) # 保留二位小数 figure = "{:.2f}".format(figure) # 人性化显示 figure = "{:,}".format(float(figure)) if kwargs.get("compel", True): # 进行处理，保留二位小数，如果不足二位补领 figure_list = figure.split(".") if len(figure_list[1]) == 1: figure += "0" return figure |
方法二：利用xToolkit库
安装方法：
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pip install xToolkit -i http://pypi.douban.com/simple --trusted-host pypi.douban.com |
xToolkit库是我自己封装的python内置库的一个扩展库.把python的datetime,string,list,dist，xthread等数据结构进行了功能的扩展。
使用方法比较简单，一行代码即可搞定
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# 金额人性化,保留二位小数xstring.dispose(3.0).humanized_amount(compel=False)xstring.dispose("3.0").humanized_amount(compel=True)xstring.dispose(37787841.902).humanized_amount(compel=False)xstring.dispose("37787841.902").humanized_amount(compel=True)xstring.dispose(378978989).humanized_amount(compel=False)xstring.dispose("378978989").humanized_amount(compel=True)>>3.0>>3.00>>37,787,841.9>>37,787,841.90>>378,978,989.0>>378,978,989.00 |
实例扩展：
用python实现把数字人民币金额转换成大写的脚本程序
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# -*- coding: utf-8 -*-def Num2MoneyFormat( change_number ): """ .转换数字为大写货币格式( format_word.__len__() - 3 + 2位小数 ) change_number 支持 float, int, long, string """ format_word = ["分", "角", "元", "拾","百","千","万", "拾","百","千","亿", "拾","百","千","万", "拾","百","千","兆"] format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"] if type( change_number ) == str: # - 如果是字符串,先尝试转换成float或int. if '.' in change_number: try: change_number = float( change_number ) except: raise ValueError, '%s can\'t change'%change_number else: try: change_number = int( change_number ) except: raise ValueError, '%s can\'t change'%change_number if type( change_number ) == float: real_numbers = [] for i in range( len( format_word ) - 3, -3, -1 ): if change_number >= 10 ** i or i < 1: real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) ) elif isinstance( change_number, (int, long) ): real_numbers = [ int( i ) for i in str( change_number ) + '00' ] else: raise ValueError, '%s can\'t change'%change_number zflag = 0 #标记连续0次数，以删除万字，或适时插入零字 start = len(real_numbers) - 3 change_words = [] for i in range(start, -3, -1): #使i对应实际位数，负数为角分 if 0 <> real_numbers[start-i] or len(change_words) == 0: if zflag: change_words.append(format_num[0]) zflag = 0 change_words.append( format_num[ real_numbers[ start - i ] ] ) change_words.append(format_word[i+2]) elif 0 == i or (0 == i%4 and zflag < 3): #控制 万/元 change_words.append(format_word[i+2]) zflag = 0 else: zflag += 1 if change_words[-1] not in ( format_word[0], format_word[1]): # - 最后两位非"角,分"则补"整" change_words.append("整") return ''.join(change_words)print Num2MoneyFormat( 343.45 ) |
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