本文实例讲述了Java中Json解析的方法。分享给大家供大家参考，具体如下：
首先准备一个JSON格式的字符串
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* String JsonStr = "{object:{persons:" +"[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," +"{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," +"{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}";* 然后定义一个Person类**class Person{ private String name,image; public String getName() { return name; } public void setName(String name) { this.name = name; } public String getImage() { return image; } public void setImage(String image) { this.image = image; }} |
下面是一个Json解析的程序代码
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class MyDay17Xml { //json字符串 static String JsonStr = "{object:{persons:" + "[{name:'呵呵',image:'http://10.0.159.132:8080/Web/s1.png'}," + "{name:'哈哈',image:'http://10.0.159.132:8080/Web/s1.png'}," + "{name:'嘿嘿',image:'http://10.0.159.132:8080/Web/s2.jpg'}]}}"; public static void main(String []args) throws JSONException{ List<Person> list=jsonStrToList(JsonStr); System.out.println(list.size()); } /** * * * */ public static List<Person> jsonStrToList(String jsonStr) throws JSONException{ List<Person> list=new ArrayList<Person>(); //通过字符串，获得最外部的json对象 JSONObject jsonObj=new JSONObject(jsonStr); //通过属性名，获得内部的对象 JSONObject jsonPersons=jsonObj.getJSONObject("object"); //获得json对象组 JSONArray arr=jsonPersons.getJSONArray("persons"); for(int i=0;i<arr.length();i++){ //循环对象，并通过getString("属性名");来获得值 JSONObject tempJson=arr.getJSONObject(i); Person person=new Person(); person.setName(tempJson.getString("name")); person.setImage(tempJson.getString("image")); list.add(person); } return list; }} |
希望本文所述对大家java程序设计有所帮助。
