Python调用微信公众平台接口操作示例_Python

本文实例讲述了Python调用微信公众平台接口操作。分享给大家供大家参考，具体如下：

这里使用的是Django,其他类似

									# coding=utf-8

									from django.http import HttpResponse

									import hashlib, time, re

									from xml.etree import ElementTree as ET

									def weixin(request):

									    token = "your token here"

									    params = request.GET

									    args = [token, params['timestamp'], params['nonce']]

									    args.sort()

									    if hashlib.sha1("".join(args)).hexdigest() == params['signature']:

									      if params.has_key('echostr'):

									      return HttpResponse(params['echostr'])

									        else:

									          reply = """<xml>

									        <ToUserName><![CDATA[%s]]></ToUserName>

									        <FromUserName><![CDATA[%s]]></FromUserName>

									              <CreateTime>%s</CreateTime>

									              <MsgType><![CDATA[text]]></MsgType>

									              <Content><![CDATA[%s]]></Content>

									              <FuncFlag>0</FuncFlag>

									          </xml>"""

									          if request.raw_post_data:

									              xml = ET.fromstring(request.raw_post_data)

									              content = xml.find("Content").text

									              fromUserName = xml.find("ToUserName").text

									              toUserName = xml.find("FromUserName").text

									              postTime = str(int(time.time()))

									                if not content:

									                  return HttpResponse(reply % (toUserName, fromUserName, postTime, "输入点命令吧..."))

									              if content == "Hello2BizUser":

									                  return HttpResponse(reply % (toUserName, fromUserName, postTime, "查询成绩绩点请到http://chajidian.sinaapp.com/ 本微信更多功能开发中..."))

									              else:

									                  return HttpResponse(reply % (toUserName, fromUserName, postTime, "暂不支持任何命令交互哦,功能开发中..."))

									      else:

									              return HttpResponse("Invalid Request")

									  else:

									      return HttpResponse("Invalid Request")

希望本文所述对大家Python程序设计有所帮助。

Python调用微信公众平台接口操作示例

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