本文实例讲述了Python实现针对含中文字符串的截取功能。分享给大家供大家参考,具体如下:
对于含多字节的字符串,进行截断的时候,要判断截断处是几字节字符,不能将多字节从中分割,避免截断后乱码
下面给出utf8和gb18030上的实现, 用任何一种都可以,可以先进行转码,用encode, decode;
方法1:对utf8:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
|
def subString(string,length): if length > = len (string): return string result = '' i = 0 p = 0 while True : ch = ord (string[i]) #1111110x if ch > = 252 : p = p + 6 #111110xx elif ch > = 248 : p = p + 5 #11110xxx elif ch > = 240 : p = p + 4 #1110xxxx elif ch > = 224 : p = p + 3 #110xxxxx elif ch > = 192 : p = p + 2 else : p = p + 1 if p > = length: break ; else : i = p return string[ 0 :i] |
方法2:对gb18030编码
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
|
def cut_string_off(string,s_len): if len (string) = = 0 or s_len < = 0 : return string elif len (string) = = 1 or s_len > = len (string): return string elif s_len < len (string): len_num = 0 while len_num < s_len: tmp_c = ord (string[len_num]) if tmp_c > 0 and tmp_c < = 0x7F : len_num + = 1 continue tmp_nextc = ord (string[len_num + 1 ]) if tmp_c > = 0x81 and tmp_c < = 0xFE and tmp_nextc> = 0x40 and tmp_nextc< = 0xFE : len_num + = 2 continue else : len_num + = 1 ; continue break tmp = string[ 0 :len_num] # print utf2gbk(tmp) return tmp |
希望本文所述对大家Python程序设计有所帮助。
原文链接:http://www.cnblogs.com/liyuxia713/p/3518689.html