本代码可以帮你自动剪切掉图片的边缘空白区域，如果你的图片有大片空白区域（只要是同一颜色形成一定的面积就认为是空白区域），下面的python代码可以帮你自动切除，如果是透明图像，会自动剪切大片的透明部分。
本代码需要PIL模块
pil相关介绍
PIL：Python Imaging Library，已经是Python平台事实上的图像处理标准库了。PIL功能非常强大，但API却非常简单易用。
由于PIL仅支持到Python 2.7，加上年久失修，于是一群志愿者在PIL的基础上创建了兼容的版本，名字叫Pillow，支持最新Python 3.x，又加入了许多新特性，因此，我们可以直接安装使用Pillow。
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
|
import Image, ImageChops def autoCrop(image,backgroundColor=None): '''Intelligent automatic image cropping. This functions removes the usless "white" space around an image. If the image has an alpha (tranparency) channel, it will be used to choose what to crop. Otherwise, this function will try to find the most popular color on the edges of the image and consider this color "whitespace". (You can override this color with the backgroundColor parameter) Input: image (a PIL Image object): The image to crop. backgroundColor (3 integers tuple): eg. (0,0,255) The color to consider "background to crop". If the image is transparent, this parameters will be ignored. If the image is not transparent and this parameter is not provided, it will be automatically calculated. Output: a PIL Image object : The cropped image. ''' def mostPopularEdgeColor(image): ''' Compute who's the most popular color on the edges of an image. (left,right,top,bottom) Input: image: a PIL Image object Ouput: The most popular color (A tuple of integers (R,G,B)) ''' im = image if im.mode != 'RGB': im = image.convert("RGB") # Get pixels from the edges of the image: width,height = im.size left = im.crop((0,1,1,height-1)) right = im.crop((width-1,1,width,height-1)) top = im.crop((0,0,width,1)) bottom = im.crop((0,height-1,width,height)) pixels = left.tostring() + right.tostring() + top.tostring() + bottom.tostring() # Compute who's the most popular RGB triplet counts = {} for i in range(0,len(pixels),3): RGB = pixels[i]+pixels[i+1]+pixels[i+2] if RGB in counts: counts[RGB] += 1 else: counts[RGB] = 1 # Get the colour which is the most popular: mostPopularColor = sorted([(count,rgba) for (rgba,count) in counts.items()],reverse=True)[0][1] return ord(mostPopularColor[0]),ord(mostPopularColor[1]),ord(mostPopularColor[2]) bbox = None # If the image has an alpha (tranparency) layer, we use it to crop the image. # Otherwise, we look at the pixels around the image (top, left, bottom and right) # and use the most used color as the color to crop. # --- For transparent images ----------------------------------------------- if 'A' in image.getbands(): # If the image has a transparency layer, use it. # This works for all modes which have transparency layer bbox = image.split()[list(image.getbands()).index('A')].getbbox() # --- For non-transparent images ------------------------------------------- elif image.mode=='RGB': if not backgroundColor: backgroundColor = mostPopularEdgeColor(image) # Crop a non-transparent image. # .getbbox() always crops the black color. # So we need to substract the "background" color from our image. bg = Image.new("RGB", image.size, backgroundColor) diff = ImageChops.difference(image, bg) # Substract background color from image bbox = diff.getbbox() # Try to find the real bounding box of the image. else: raise NotImplementedError, "Sorry, this function is not implemented yet for images in mode '%s'." % image.mode if bbox: image = image.crop(bbox) return image #范例：裁剪透明图片:im = Image.open('myTransparentImage.png')cropped = autoCrop(im)cropped.show() #范例：裁剪非透明图片im = Image.open('myImage.png')cropped = autoCrop(im)cropped.show() |
总结
以上就是本文关于python自动裁剪图像代码分享的全部内容，希望对大家有所帮助。
原文链接：http://www.open-open.com/code/view/1422101378093
