有部分老项目是在Eclipse环境开发的,最近公司要求应用瘦身,老项目也在其中。如果在 AS 下开发就不会有这样的问题,但是在 Eclipse 中就不太方便了,于是就写了这个脚本。第一次用Python写东西,代码里可能会有许多 Java、C 这样的痕迹,见谅。
使用方法
将 python 目录下的 delUnused.py 放到项目目录下,然后直接运行即可。
代码说明
利用lint进行代码审查
1
|
lint - - check UnusedResources - - xml [resultPath] [projectPath] |
命令含义是检查项目中未使用的资源文件,并且用xml格式输出结果,需要提供检查结果输出的路径和项目路径。在脚本中已经自动提供了。
1
2
3
4
5
6
7
|
def exec_lint_command(): cmd = 'lint --check UnusedResources --xml %s %s' % (_get_lint_result_path(), _get_project_dir_path()) p = subprocess.Popen(cmd, shell = True , stdout = subprocess.PIPE, stdin = subprocess.PIPE, stderr = subprocess.PIPE) c = p.stdout.readline().decode() while c: print (c) c = p.stdout.readline().decode() |
这里给一个检查结果实例吧
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
|
<issue id = "UnusedResources" severity = "Warning" message = "The resource `R.layout.activity_all_player` appears to be unused" category = "Performance" priority = "3" summary = "Unused resources" explanation = "Unused resources make applications larger and slow down builds." errorLine1 = "<LinearLayout xmlns:android=" http: / / schemas.android.com / apk / res / android" " errorLine2 = "^" quickfix = "studio" > <location file = "res\layout\activity_all_player.xml" line = "2" column = "1" / > < / issue> |
我们能用到的信息有 id message location 等。
解析检查结果
我是利用 minidom 解析的,具体的解析方法不多说,参考。
获取根节点
1
2
3
4
5
|
def _parse_lint_report(): file = minidom.parse(_get_lint_result_path()) root = file .documentElement beans = _parse_xml(root) return beans |
解析第一层子节点
1
2
3
4
5
6
7
8
9
10
11
12
13
|
def _parse_xml(element, beans = None ): if beans is None : beans = [] for node in element.childNodes: if node.nodeName = = ISSUE_KEY and node.nodeType is node.ELEMENT_NODE: lint_bean = _LintBean() lint_bean. id = node.getAttribute(ID_KEY) lint_bean.severity = node.getAttribute(SEVERITY_KEY) lint_bean.message = node.getAttribute(MESSAGE_KEY) _parse_location(node, lint_bean) lint_bean. print () beans.append(lint_bean) return beans |
解析location 子节点
1
2
3
4
5
6
7
8
|
def _parse_location(node, bean): if not node.hasChildNodes(): return for child in node.childNodes: if child.nodeName = = LOCATION_KEY and node.nodeType is node.ELEMENT_NODE: bean.location. file = child.getAttribute(LOCATION_FILE_KEY) bean.location.line = child.getAttribute(LOCATION_LINE_KEY) bean.location.column = child.getAttribute(LOCATION_COLUMN_KEY) |
用Java习惯了,解析数据喜欢用Bean
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
|
class _Location( object ): def __init__( self ): self . file = '' self .line = 0 self .column = 0 class _LintBean( object ): def __init__( self ): self . id = '' self .severity = '' self .message = '' self .location = _Location() def print ( self ): print ( 'find a %s, cause: %s. filePath: %s. line: %s' % ( self . id , self .message, self .location. file , self .location.line)) |
处理无用资源
解析完数据,可以得到三种资源:
- Drawable,就一个文件,可以直接删
- xml中的一个节点,但是这个xml中就这一个节点,直接删文件
- xml中的一个节点,这个xml中有多个节点,删除节点
对这三种资源进行区分和删除
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
|
for lint in lint_result: total_unused_resource + = 1 if lint. id ! = 'UnusedResources' : continue if lint.location.line ! = '': is_single = _is_single_node(lint.location. file ) if is_single: total_del_file + = 1 del_file(lint.location. file ) else : total_remove_attr + = 1 node_name = get_node_name(lint.message) del_node(lint.location. file , node_name) else : total_del_file + = 1 del_file(lint.location. file ) |
删除文件
1
2
3
4
5
6
|
def del_file(file_path): try : os.remove(file_path) print ( 'remove %s success.' % file_path) except FileNotFoundError: print ( 'remove %s error.' % file_path) |
删除节点:
1
2
3
4
5
6
7
8
9
10
11
12
|
def del_node(file_path, node_name): file = minidom.parse(file_path) root = file .documentElement nodes = root.childNodes for node in nodes: if node.nodeType in (node.TEXT_NODE, node.COMMENT_NODE): continue if node_name = = node.getAttribute( 'name' ): root.removeChild(node) file .writexml( open (file_path, 'w' , encoding = 'UTF-8' ), encoding = 'UTF-8' ) print ( 'remove %s, node_name:%s. success!' % (file_path, node_name)) return |
总结
以上所述是小编给大家介绍的使用python 和 lint 删除项目无用资源的方法,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!
原文链接:https://juejin.im/post/5a39ccc65188251fbd33c37f?utm_source=tuicool&utm_medium=referral