本文实例讲述了PHP查询附近的人及其距离的实现方法。分享给大家供大家参考，具体如下：
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
|
<?php//获取该点周围的4个点$distance = 1;//范围（单位千米）$lat = 113.873643;$lng = 22.573969;define('EARTH_RADIUS', 6371);//地球半径，平均半径为6371km$dlng = 2 * asin(sin($distance / (2 * EARTH_RADIUS)) / cos(deg2rad($lat)));$dlng = rad2deg($dlng);$dlat = $distance/EARTH_RADIUS;$dlat = rad2deg($dlat);$squares = array('left-top'=>array('lat'=>$lat + $dlat,'lng'=>$lng-$dlng), 'right-top'=>array('lat'=>$lat + $dlat, 'lng'=>$lng + $dlng), 'left-bottom'=>array('lat'=>$lat - $dlat, 'lng'=>$lng - $dlng), 'right-bottom'=>array('lat'=>$lat - $dlat, 'lng'=>$lng + $dlng) );print_r($squares['left-top']['lat']);//从数库查询匹配的记录$info_sql = "select * from `A` where lat<>0 and lat>{$squares['right-bottom']['lat']} and lat<{$squares['left-top']['lat']} and lng>{$squares['left-top']['lng']} and lng<{$squares['right-bottom']['lng']} ";//获取两点之间的距离function getDistanceBetweenPointsNew($latitude1, $longitude1, $latitude2, $longitude2) { $theta = $longitude1 - $longitude2; $miles = (sin(deg2rad($latitude1)) * sin(deg2rad($latitude2))) + (cos(deg2rad($latitude1)) * cos(deg2rad($latitude2)) * cos(deg2rad($theta))); $miles = acos($miles); $miles = rad2deg($miles); $miles = $miles * 60 * 1.1515; $feet = $miles * 5280; $yards = $feet / 3; $kilometers = $miles * 1.609344; $meters = $kilometers * 1000; return compact('miles','feet','yards','kilometers','meters'); }$point1 = array('lat' => 40.770623, 'long' => -73.964367);$point2 = array('lat' => 40.758224, 'long' => -73.917404);$distance = getDistanceBetweenPointsNew($point1['lat'], $point1['long'], $point2['lat'], $point2['long']);foreach ($distance as $unit => $value) { echo $unit.': '.number_format($value,4).'<br />';}?> |
希望本文所述对大家PHP程序设计有所帮助。
