本文实例讲述了php+html5+ajax实现上传图片的方法。分享给大家供大家参考,具体如下:
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<?php if (isset( $_POST [ 'upload' ])) { var_dump( $_FILES ); move_uploaded_file( $_FILES [ 'upfile' ][ 'tmp_name' ], 'up_tmp/' .time(). '.dat' ); //header('location: test.php'); exit ; } ?> |
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<!doctype html> <html lang= "zh" > <head> <meta charset= "utf-8" > <title>HTML5 Ajax Uploader</title> <script src= "jquery-2.1.1.min.js" ></script> </head> <body> <p><input type= "file" id= "upfile" ></p> <p><input type= "button" id= "upJS" value= "用原生JS上传" ></p> <p><input type= "button" id= "upJQuery" value= "用jQuery上传" ></p> <script> /*原生JS版*/ document.getElementById( "upJS" ).onclick = function () { /* FormData 是表单数据类 */ var fd = new FormData(); var ajax = new XMLHttpRequest(); fd.append( "upload" , 1); /* 把文件添加到表单里 */ fd.append( "upfile" , document.getElementById( "upfile" ).files[0]); ajax.open( "post" , "test.php" , true ); ajax.onload = function () { console.log(ajax.responseText); }; ajax.send(fd); } /* jQuery 版 */ $( '#upJQuery' ).on( 'click' , function () { var fd = new FormData(); fd.append( "upload" , 1); fd.append( "upfile" , $( "#upfile" ).get(0).files[0]); $.ajax({ url: "test.php" , type: "POST" , processData: false , contentType: false , data: fd, success: function (d) { console.log(d); } }); }); </script> </body> </html> |
希望本文所述对大家PHP程序设计有所帮助。