ajax.php：
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<head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>Untitled Document</title></head><script language="javascript">function saveUserInfo(){//获取接受返回信息层var msg = document.getElementByIdx_x("msg");//获取表单对象和用户信息值var f = document.user_info;var userName = f.user_name.value;var userAge = f.user_age.value;var userSex = f.user_sex.value;//接收表单的URL地址var url = "./ajax_output.php";//需要POST的值，把每个变量都通过&来联接var postStr = "user_name="+ userName +"&user_age="+ userAge +"&user_sex="+ userSex;//实例化Ajax//var ajax = InitAjax(); var ajax = false; //开始初始化XMLHttpRequest对象 if(window.XMLHttpRequest) { //Mozilla 浏览器 ajax = new XMLHttpRequest(); if (ajax.overrideMimeType) {//设置MiME类别 ajax.overrideMimeType("text/xml"); } } else if (window.ActiveXObject) { // IE浏览器 try { ajax = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { ajax = new ActiveXObject("Microsoft.XMLHTTP"); } catch (e) {} } } if (!ajax) { // 异常，创建对象实例失败 window.alert("不能创建XMLHttpRequest对象实例."); return false; } //通过Post方式打开连接ajax.open("POST", url, true);//定义传输的文件HTTP头信息ajax.setRequestHeader("Content-Type","application/x-www-form-urlencoded");//发送POST数据ajax.send(postStr);//获取执行状态ajax.onreadystatechange = function() { //如果执行状态成功，那么就把返回信息写到指定的层里 if (ajax.readyState == 4 && ajax.status == 200) { msg.innerHTML = ajax.responseText; }}alert (userName);}</script><body ><div id="msg"></div><form name="user_info" method="post" action="">姓名：<input type="text" id="user_name"name="user_name" /><br />年龄：<input type="text" name="user_age" /><br />性别：<input type="text" name="user_sex" /><br /><input type="button" value="提交表单" onClick="saveUserInfo()"></form></body> |
ajax_output.php：
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<?php $username = $_POST['user_name']; $userage = $_POST['user_age']; $usersex = $_POST['user_sex']; echo "$username <br>"; echo "$userage <br>"; echo "$usersex <br>"; $db = new mysqli('localhost','root','123456','test'); if(!$db){ echo "连接失败！"; } $db->query("set names utf8"); $query = "insert into userinfo(uname,uage,usex) values ('".$username."','".$userage."','".$usersex."')"; $result = $db->query($query); if ($result){ echo "上传成功！"; } else { echo "失败！"; } $db->close();?> |
以上这篇AJAX PHP无刷新form表单提交的简单实现(推荐)就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。
