今天有朋友问我一道面试题,有5个人抢5个红包,可重复抢,用多线程程序实现,实现方式有多种,分享一下我的思路:应用了阻塞队列的特性。
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/** * Created by zhanglinqiang on 2016/6/23. */ public class MyTest { public static void main(String[] args) throws InterruptedException { LinkedBlockingQueue<LuckyMoney> luckyMoneys = new LinkedBlockingQueue<>(); List<FutureTask> futureTasks = new ArrayList<>(); //准备抢红包 for ( int i = 0 ; i < 5 ; i++) { FutureTask<Object> futureTask = new FutureTask<>( new CatchLuckMoney(luckyMoneys, "name" + i), null ); new Thread(futureTask, "name" +i).start(); futureTasks.add(futureTask); } Thread.sleep( 5 ); //确保抢红包线程准备就绪 Random random = new Random( 100 ); //发5个红包 for ( int i = 0 ; i < 5 ; i++) { luckyMoneys.put( new LuckyMoney( "红包" +i, random.nextInt( 100 )+ 1 )); } //等到红包抢完 while (!luckyMoneys.isEmpty()){ Thread.sleep( 1 ); } //终止抢红包线程 for (FutureTask futureTask : futureTasks) { futureTask.cancel( true ); } } } class CatchLuckMoney implements Runnable { public CatchLuckMoney(LinkedBlockingQueue<LuckyMoney> luckyMoneys, String name) { this .luckyMoneys = luckyMoneys; this .name = name; } private LinkedBlockingQueue<LuckyMoney> luckyMoneys; private String name; @Override public void run() { while (!Thread.currentThread().isInterrupted()) { LuckyMoney redPackage = null ; try { redPackage = luckyMoneys.take(); } catch (InterruptedException e) { // e.printStackTrace(); break ; } System.out.println(name + "抢到了-->" + redPackage); luckyMoneys.remove(redPackage); } System.out.println( "end>>>>>>>>>>>>>>>>>>>>>>>>>>>>" +Thread.currentThread().getName()); } } class LuckyMoney { public LuckyMoney(String name, Integer money) { this .name = name; this .money = money; } private String name; private Integer money; @Override public String toString() { return "LuckyMoney{" + "name='" + name + '\ '' + ", money=" + money + '}' ; } } |
运行效果:
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Connected to the target VM, address: '127.0.0.1:8869' , transport: 'socket' name3抢到了-->LuckyMoney{name= '红包0' , money= 16 } name4抢到了-->LuckyMoney{name= '红包3' , money= 89 } name0抢到了-->LuckyMoney{name= '红包2' , money= 75 } name1抢到了-->LuckyMoney{name= '红包1' , money= 51 } name3抢到了-->LuckyMoney{name= '红包4' , money= 92 } end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name0 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name4 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name3 Disconnected from the target VM, address: '127.0.0.1:8869' , transport: 'socket' end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name1 end>>>>>>>>>>>>>>>>>>>>>>>>>>>>name2 Process finished with exit code 0 |
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原文链接:http://blog.csdn.net/u011411069/article/details/52503835