本文实例为大家分享了python实现人民币转大写人民币的具体代码，供大家参考，具体内容如下
直接上代码：
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# -*- coding: utf-8 -*-def changenum( change_number ): format_num = ["零","壹","贰","叁","肆","伍","陆","柒","捌","玖"] format_name = ["分", "角", "元", "拾","百","千","万", "拾","百","千","亿", "拾","百","千","万", "拾","百","千","兆"] if type( change_number ) == str: if '.' in change_number: try: change_number = float( change_number ) except: raise ValueError, '%s can\'t change'%change_number else: try: change_number = int( change_number ) except: raise ValueError, '%s can\'t change'%change_number if type( change_number ) == float: real_numbers = [] for i in range( len( format_name ) - 3, -3, -1 ): if change_number >= 10 ** i or i < 1: real_numbers.append( int( round( change_number/( 10**i ), 2)%10 ) ) elif isinstance( change_number, (int, long) ): real_numbers = [ int( i ) for i in str( change_number ) + '00' ] else: raise ValueError, '%s can\'t change'%change_number zflag = 0 start = len(real_numbers) - 3 change_words = [] for i in range(start, -3, -1): if 0 <> real_numbers[start-i] or len(change_words) == 0: if zflag: change_words.append(format_num[0]) zflag = 0 change_words.append( format_num[ real_numbers[ start - i ] ] ) change_words.append(format_name [i+2]) elif 0 == i or (0 == i%4 and zflag < 3): change_words.append(format_name [i+2]) zflag = 0 else: zflag += 1 if change_words[-1] not in (format_name[0], format_name[1]): change_words.append("整") return ''.join(change_words)#测试# print changenum(865324.98)#查看输出的结果是否正确 |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/haeasringnar/article/details/79523836
