本文实例讲述了Python根据已知邻接矩阵绘制无向图操作。分享给大家供大家参考,具体如下:
有六个点:[0,1,2,3,4,5,6],六个点之间的邻接矩阵如表格所示,根据邻接矩阵绘制出相对应的图
|
0 |
1 |
2 |
3 |
4 |
5 |
6 |
0 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
1 |
1 |
0 |
1 |
1 |
1 |
1 |
1 |
2 |
0 |
1 |
0 |
1 |
0 |
1 |
0 |
3 |
1 |
1 |
1 |
0 |
1 |
1 |
1 |
4 |
0 |
1 |
0 |
1 |
1 |
1 |
1 |
5 |
1 |
1 |
1 |
1 |
1 |
0 |
0 |
6 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
将点之间的联系构造成如下矩阵
N = [[0, 3, 5, 1],
[1, 5, 4, 3],
[2, 1, 3, 5],
[3, 5, 1, 4],
[4, 5, 1, 3],
[5, 3, 4, 1],
[6, 3, 1, 4]]
代码如下
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
|
# -*- coding:utf-8 -*- #! python3 import networkx as nx import matplotlib.pyplot as plt G = nx.Graph() point = [ 0 , 1 , 2 , 3 , 4 , 5 , 6 ] G.add_nodes_from(point) edglist = [] N = [[ 0 , 3 , 5 , 1 ],[ 1 , 5 , 4 , 3 ],[ 2 , 1 , 3 , 5 ],[ 3 , 5 , 1 , 4 ],[ 4 , 5 , 1 , 3 ],[ 5 , 3 , 4 , 1 ],[ 6 , 3 , 1 , 4 ]] for i in range ( 7 ): for j in range ( 1 , 4 ): edglist.append((N[i][ 0 ],N[i][j])) G = nx.Graph(edglist) position = nx.circular_layout(G) nx.draw_networkx_nodes(G,position, nodelist = point, node_color = "r" ) nx.draw_networkx_edges(G,position) nx.draw_networkx_labels(G,position) plt.show() |
显示结果:
希望本文所述对大家Python程序设计有所帮助。
原文链接:https://blog.csdn.net/weixin_40198632/article/details/78418714