本文实例讲述了Java实现的剪刀石头布游戏。分享给大家供大家参考，具体如下：
ChoiceAnswer.java
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public class ChoiceAnswer { String texts[] = { "石头", "剪刀", "布" }; int value; // 【1】石头\t【2】剪刀\t【3】布 String getText() { return texts[value - 1]; } ChoiceAnswer(int value) { this.value = value; } /** * 返回0表示平手，返回1表示赢，返回-1表示输 */ int compTo(ChoiceAnswer c) { if (value == c.value) { return 0; } if (value + 1 == c.value || (value == 3 && c.value == 1)) { return 1; } return -1; }} |
Game.java
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import java.util.Scanner;public class Game { void p(String s) { System.out.println(s); } void showWelcome() { p("欢迎使用······"); p("请选择：【1】石头\t【2】剪刀\t【3】布"); } @SuppressWarnings("resource") ChoiceAnswer getUserChoice() { Scanner sc = new Scanner(System.in); int userChoice = Integer.parseInt(sc.nextLine()); while (userChoice < 1 || userChoice > 3) { p("你输入的不正确！请重新输入！"); userChoice = Integer.parseInt(sc.nextLine()); } return new ChoiceAnswer(userChoice); } ChoiceAnswer getComputerChoice() { int computerChoice = (int) ((Math.random() * 3) + 1); return new ChoiceAnswer(computerChoice); } void showResult(ChoiceAnswer userChoice, ChoiceAnswer computerChoice) { int result = userChoice.compTo(computerChoice); if (result == 0) { System.out.println("平手,您和电脑均选择了：" + userChoice.getText()); } else if (result == 1) { System.out.println("恭喜,您赢了！您选择了：" + userChoice.getText() + "; 电脑选择了：" + computerChoice.getText()); } else { System.out.println("对不起,您败了！您选择了：" + userChoice.getText() + ";电脑选择了：" + computerChoice.getText()); } } void start() { showWelcome(); ChoiceAnswer userChoice = getUserChoice(); ChoiceAnswer computerChoice = getComputerChoice(); showResult(userChoice, computerChoice); } public static void main(String a[]) { System.out.println("服务器之家测试结果："); new Game().start(); }} |
运行结果：
希望本文所述对大家java程序设计有所帮助。
原文链接：http://blog.csdn.net/wenzhilanyu2012/article/details/8733661
