WORD 两个字节 16bit
DWORD 四个字节 32bit
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package main import ( "encoding/binary" "fmt" "os") func main() { file, err := os.Open("tim.bmp") if err != nil { fmt.Println(err) return } defer file.Close() //type拆成两个byte来读 var headA, headB byte //Read第二个参数字节序一般windows/linux大部分都是LittleEndian,苹果系统用BigEndian binary.Read(file, binary.LittleEndian, &headA) binary.Read(file, binary.LittleEndian, &headB) //文件大小 var size uint32 binary.Read(file, binary.LittleEndian, &size) //预留字节 var reservedA, reservedB uint16 binary.Read(file, binary.LittleEndian, &reservedA) binary.Read(file, binary.LittleEndian, &reservedB) //偏移字节 var offbits uint32 binary.Read(file, binary.LittleEndian, &offbits) fmt.Println(headA, headB, size, reservedA, reservedB, offbits) } |
执行结果
66 77 196662 0 0 54
使用结构体方式
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package main import ( "encoding/binary" "fmt" "os") type BitmapInfoHeader struct { Size uint32 Width int32 Height int32 Places uint16 BitCount uint16 Compression uint32 SizeImage uint32 XperlsPerMeter int32 YperlsPerMeter int32 ClsrUsed uint32 ClrImportant uint32} func main() { file, err := os.Open("tim.bmp") if err != nil { fmt.Println(err) return } defer file.Close() //type拆成两个byte来读 var headA, headB byte //Read第二个参数字节序一般windows/linux大部分都是LittleEndian,苹果系统用BigEndian binary.Read(file, binary.LittleEndian, &headA) binary.Read(file, binary.LittleEndian, &headB) //文件大小 var size uint32 binary.Read(file, binary.LittleEndian, &size) //预留字节 var reservedA, reservedB uint16 binary.Read(file, binary.LittleEndian, &reservedA) binary.Read(file, binary.LittleEndian, &reservedB) //偏移字节 var offbits uint32 binary.Read(file, binary.LittleEndian, &offbits) fmt.Println(headA, headB, size, reservedA, reservedB, offbits) infoHeader := new(BitmapInfoHeader) binary.Read(file, binary.LittleEndian, infoHeader) fmt.Println(infoHeader) } |
执行结果：
66 77 196662 0 0 54
&{40 256 256 1 24 0 196608 3100 3100 0 0}
补充：golang(Go语言) byte/[]byte 与 二进制形式字符串 互转
效果
把某个字节或字节数组转换成字符串01的形式，一个字节用8个”0”或”1”字符表示。
比如：
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byte(3) –> “00000011”[]byte{1,2,3} –> “[00000001 00000010 00000011]”“[00000011 10000000]” –> []byte{0x3, 0x80} |
开源库 biu
实际上我已经将其封装到一个开源库了(biu)，其中的一个功能就能达到上述效果：
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//byte/[]byte -> stringbs := []byte{1, 2, 3}s := biu.BytesToBinaryString(bs)fmt.Println(s) //[00000001 00000010 00000011]fmt.Println(biu.ByteToBinaryString(byte(3))) //00000011//string -> []bytes := "[00000011 10000000]"bs := biu.BinaryStringToBytes(s)fmt.Printf("%#v\n", bs) //[]byte{0x3, 0x80} |
代码实现
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const ( zero = byte('0') one = byte('1') lsb = byte('[') // left square brackets rsb = byte(']') // right square brackets space = byte(' '))var uint8arr [8]uint8// ErrBadStringFormat represents a error of input string's format is illegal .var ErrBadStringFormat = errors.New("bad string format")// ErrEmptyString represents a error of empty input string.var ErrEmptyString = errors.New("empty string")func init() { uint8arr[0] = 128 uint8arr[1] = 64 uint8arr[2] = 32 uint8arr[3] = 16 uint8arr[4] = 8 uint8arr[5] = 4 uint8arr[6] = 2 uint8arr[7] = 1}// append bytes of string in binary format.func appendBinaryString(bs []byte, b byte) []byte { var a byte for i := 0; i < 8; i++ { a = b b <<= 1 b >>= 1 switch a { case b: bs = append(bs, zero) default: bs = append(bs, one) } b <<= 1 } return bs}// ByteToBinaryString get the string in binary format of a byte or uint8.func ByteToBinaryString(b byte) string { buf := make([]byte, 0, 8) buf = appendBinaryString(buf, b) return string(buf)}// BytesToBinaryString get the string in binary format of a []byte or []int8.func BytesToBinaryString(bs []byte) string { l := len(bs) bl := l*8 + l + 1 buf := make([]byte, 0, bl) buf = append(buf, lsb) for _, b := range bs { buf = appendBinaryString(buf, b) buf = append(buf, space) } buf[bl-1] = rsb return string(buf)}// regex for delete useless string which is going to be in binary format.var rbDel = regexp.MustCompile(`[^01]`)// BinaryStringToBytes get the binary bytes according to the// input string which is in binary format.func BinaryStringToBytes(s string) (bs []byte) { if len(s) == 0 { panic(ErrEmptyString) } s = rbDel.ReplaceAllString(s, "") l := len(s) if l == 0 { panic(ErrBadStringFormat) } mo := l % 8 l /= 8 if mo != 0 { l++ } bs = make([]byte, 0, l) mo = 8 - mo var n uint8 for i, b := range []byte(s) { m := (i + mo) % 8 switch b { case one: n += uint8arr[m] } if m == 7 { bs = append(bs, n) n = 0 } } return} |
以上为个人经验，希望能给大家一个参考，也希望大家多多支持服务器之家。如有错误或未考虑完全的地方，望不吝赐教。
原文链接：https://www.cnblogs.com/saryli/p/11064837.html
