本文实例讲述了jQuery+php简单实现全选删除的方法。分享给大家供大家参考,具体如下:
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< input type = "checkbox" id = "ckb_selectAll" onclick = "selectAll()" title = "选中/取消选中" > < a href = "javascript:void(0);" onclick = "del_()" title = "删除选定数据" style = "font-weight:normal" >删除</ a > |
↑全选checkbox
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< input type = "checkbox" class = "ckb" id = "+con.id+" value = "+con.id+" > |
↑为删除项,同一命名class为ckb,方便操作,同时将id值巧妙的放入input中,方便获取。
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function selectAll() { if ($( '#ckb_selectAll' ).is( ':checked' )) { $( ".ckb" ).attr( "checked" , true ); //全部选中 } else { $( ".ckb" ).attr( "checked" , false ); //全部取消 } } |
↑选中事件
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function del_() { var ids = '' ; $( ".ckb" ).each( function () { if ($( this ).is( ':checked' )) { ids += ',' + $( this ).val(); //逐个获取id } }); ids = ids.substring(1); // 对id进行处理,去除第一个逗号 if (ids.length == 0) { alert( '请选择要删除的选项' ); } else { if (confirm( "确定删除?删除后将无法恢复。" )) { url = "action=del_call_record&ids=" + ids; $.ajax({ type: "post" , url: "send.php" , data: url, success: function (json) { if (parseInt(json.counts) > 0) { alert(json.des); location.reload(); } else { alert(json.des); } }, error: function (XMLHttpRequest, textStatus) { alert( "页面请求错误,请检查重试或联系管理员!\n" + textStatus); } }); } } } |
↑删除用ajax来处理。
↓后台操作数据库,处理删除动作。
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$ids = trim( $_REQUEST [ 'ids' ]); $del_sql = "DELETE FROM vicidial_call_record WHERE id IN(" . $ids . ")" ; //print_r($del_sql);exit; if (mysqli_query( $db_conn , $del_sql )) { $counts = "1" ; $des = "成功" ; } else { $counts = "0" ; $des = "失败" ; } $json_data = "{" ; $json_data . = "\"counts\":" .json_encode( $counts ). "," ; $json_data . = "\"des\":" .json_encode( $des ). "" ; $json_data . = "}" ; echo $json_data ; break ; |
完成
希望本文所述对大家PHP程序设计有所帮助。