代码很简单,这里就不多废话了,直接奉上:
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#include <iostream> using namespace std; int * reverse( int * list, int size) { for ( int i = 0, j = size - 1; i < j; i++, j--) { // Swap list[i] with list[j] int temp = list[j]; list[j] = list[i]; list[i] = temp; } return list; } void printArray( int * const list, int size) { for ( int i = 0; i < size; i++) cout << list[i] << " " ; } int main() { int list[] = {1, 2, 3, 4, 5, 6}; int * p = reverse(list, 6); printArray(p, 6); return 0; } |
另附上一则网友的写法
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#include<math.h> int main( void ) { char c[100][100]; int i=0,j; char a; while (1) { scanf ( "%s%c" ,c[i],&a); if (a== '\n' ) { break ; } i++; } for (j=i; j>=0; j--) { printf ( "%s " ,c[j]); } return 0; } |