C++ 重载+运算符重载加号 实现矩阵相加
学习C++ 基础知识,这里实现简单的实例,记录下自己学习生活,很简单,大家一起看看吧!
实例代码:
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#include<iostream> #include<iomanip> using namespace std; class Complex { private : int i,j,n,a[2][3]; public : Complex(); Complex operator+(Complex &c); void display(); void input(); } t1; Complex::Complex() { for ( int i=0;i<2;i++) for ( int j=0;j<3;j++) a[i][j]=0; } void Complex::input() { for (i=0;i<2;i++) for (j=0;j<3;j++) cin>>a[i][j]; } void Complex::display() { n=1; for (i=0;i<2;i++) for (j=0;j<3;j++) { n++; if (n%2==0) cout<<endl; cout<<setw(5)<<a[i][j]; } cout<<endl; } Complex Complex::operator+(Complex &c) { for ( int i=0;i<2;i++) for ( int j=0;j<3;j++) t1.a[i][j]=a[i][j]+c.a[i][j]; return t1; } int main() { Complex t2,t3,t4; cout<< "请输入2*3个整数" <<endl; t2.input(); cout<<endl; cout<< "请输入2*3个整数" <<endl; t3.input(); cout<<endl; cout<< "t2" ; t2.display(); cout<< "t3" ; t3.display(); t4=t2+t3; cout<< "t4=t2+t3=" ; t4.display(); return 0; } |
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原文链接:http://blog.csdn.net/hubaoquanu/article/details/51606675