背景：有一个list，里面的每一个元素都是dict，根据某一个key进行去重，在这里，key代表question
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#!/usr/bin/env python# -*- coding: utf-8 -*-# created by fhqplzj on 2017/12/07 上午11:38from itertools import groupbyfrom operator import itemgetter import pandas as pd def distinct(items): questions = map(itemgetter('question'), items) df = pd.DataFrame({ 'items': items, 'questions': questions }) return df.drop_duplicates(['questions'])['items'].tolist() def distinct2(items): exist_questions = set() result = [] for item in items: question = item['question'] if question not in exist_questions: exist_questions.add(question) result.append(item) return result def distinct3(items): key = itemgetter('question') items = sorted(items, key=key) return [next(v) for _, v in groupby(items, key=key)] def distinct4(items): from itertools import compress mask = (~pd.Series(map(itemgetter('question'), items)).duplicated()).tolist() return list(compress(items, mask)) if __name__ == '__main__': data = [ {'question': 'a', 'ans': 'b'}, {'question': 'b', 'ans': 'd'}, {'question': 'a', 'ans': 'p'}, {'question': 'b', 'ans': 'e'} ] print distinct4(data) |
以上这篇python去重,一个由dict组成的list的去重示例就是小编分享给大家的全部内容了，希望能给大家一个参考，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/ASD991936157/article/details/78740610
