本文实例讲述了C语言实现查看进程是否存在的方法。分享给大家供大家参考,具体如下:
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#include<unistd.h> #include<sys/types.h> #include<sys/wait.h> #include<stdio.h> #include<stdlib.h> #include<fcntl.h> #include<limits.h> #define BUFSZ 150 void err_quit( char *msg) { perror (msg); exit (EXIT_FAILURE); } int main( int argc, char *argv[]) { FILE * fp; int count; char buf[BUFSZ]; char command[150]; sprintf (command, "ps -ef | grep **** | grep -v grep | wc -l" ); if ((fp = popen(command, "r" )) == NULL) err_quit( "popen" ); if ( ( fgets (buf,BUFSZ,fp))!= NULL ) { count = atoi (buf); if (count == 0) printf ( "not found\n" ); else printf ( "process :tdv1 total is %d\n" ,count); } pclose(fp); exit (EXIT_SUCCESS); } |
希望本文所述对大家C语言程序设计有所帮助。