总有一些程序在windows平台表现不稳定,动不动一段时间就无响应,但又不得不用,每次都是发现问题了手动重启,现在写个脚本定时检测进程是否正常,自动重启。
涉及知识点
- schedule定时任务调度
- os.popen运行程序并读取解析运行结果
代码分解
脚本主入口
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if __name__ = = '__main__' : #每5秒执行检查任务 schedule.every( 5 ).seconds.do(check_job) #此处固定写法,意思是每秒钟schedule看下是否有pending的任务,有就执行 while true: schedule.run_pending() time.sleep( 1 ) |
schedule的其它示例
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import schedule import time def job(message = 'stuff' ): print ( "i'm working on:" , message) #每10分钟 schedule.every( 10 ).minutes.do(job) #每小时 schedule.every().hour.do(job, message = 'things' ) #每天10点30分 schedule.every().day.at( "10:30" ).do(job) while true: schedule.run_pending() time.sleep( 1 ) |
检查无响应进程并重启
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def check_job(): process_name = "xx.exe" not_respond_list = list_not_response(process_name) if len (not_respond_list) < = 0 : return pid_params = " " .join([ "/pid " + pid for pid in not_respond_list]) os.popen( "taskkill /f " + pid_params) if len (list_process(process_name)) < = 0 : start_program(r 'e:\xx\xx.exe' ) } |
查找符合条件的进程列表
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def list_process(process_name, not_respond = false): cmd = 'tasklist /fi "imagename eq %s"' if not_respond: cmd = cmd + ' /fi "status eq not responding"' output = os.popen(cmd % process_name) return parse_output(output.read()) def list_not_response(process_name): return list_process(process_name, true) |
解析命令执行结果
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def parse_output(output): print (output) pid_list = [] lines = output.strip().split( "\n" ) if len (lines) > 2 : for line in lines[ 2 :]: pid_list.append(line.split()[ 1 ]) return pid_list |
tasklist示例输出
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映像名称 pid 会话名 会话 # 内存使用 = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = wizchromeprocess.exe 1620 console 1 32 , 572 k |
完整代码
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import os import time import schedule def parse_output(output): print (output) pid_list = [] lines = output.strip().split( "\n" ) if len (lines) > 2 : for line in lines[ 2 :]: pid_list.append(line.split()[ 1 ]) return pid_list def list_not_response(process_name): return list_process(process_name, true) def list_process(process_name, not_respond = false): cmd = 'tasklist /fi "imagename eq %s"' if not_respond: cmd = cmd + ' /fi "status eq not responding"' output = os.popen(cmd % process_name) return parse_output(output.read()) def start_program(program): os.popen(program) def check_job(): process_name = "xx.exe" not_respond_list = list_not_response(process_name) if len (not_respond_list) < = 0 : return pid_params = " " .join([ "/pid " + pid for pid in not_respond_list]) os.popen( "taskkill /f " + pid_params) if len (list_process(process_name)) < = 0 : start_program(r 'e:\xxx\xx.exe' ) if __name__ = = '__main__' : schedule.every( 5 ).seconds.do(check_job) while true: schedule.run_pending() time.sleep( 1 ) |
总结
以上所述是小编给大家介绍的python定时检测无响应进程并重启的实例代码 ,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!
如果你觉得本文对你有帮助,欢迎转载,烦请注明出处,谢谢!原文链接:http://www.xetlab.com/2019/04/21/