1.两个标靶数据
2.匹配结果
3.代码
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#include <iostream> #include <vector> #include <math.h> using namespace std; struct Point { int id; float x,y,z; Point( int _id, float _x, float _y, float _z):id(_id),x(_x),y(_y),z(_z){} }; struct Triangle { Point p1,p2,p3; }; class PointCloud { public : bool readFile( char *filename); //void PointMatch(const PointCloud& pc1,const PointCloud &pc2); vector<Point> pData; int r,g,b; }; bool PointCloud::readFile( char *filename) { if (filename==NULL) return false ; FILE *fp= fopen (filename, "r" ); if (!fp) { printf ( "Load file %s failed\n" , filename); return false ; } char buffer[100]; int count=0; while (! feof (fp)) { fgets (buffer, 300, fp); float x,y,z; sscanf_s(buffer, "%f%f%f" ,&x,&y,&z); Point p(count++,x,y,z); pData.push_back(p); } pData.pop_back(); } float calDis( const Point &p1, const Point &p2) { return sqrt ((p2.x-p1.x)*(p2.x-p1.x)+(p2.y-p1.y)*(p2.y-p1.y)+(p2.z-p1.z)*(p2.z-p1.z)); } void PointMatch( const PointCloud& pc1, const PointCloud &pc2) { for ( int i=0;i<pc1.pData.size()-2;++i) for ( int j=i+1;j<pc1.pData.size()-1;++j) for ( int k=j+1;k<pc1.pData.size();++k) { Point p1=pc1.pData[i]; Point p2=pc1.pData[j]; Point p3=pc1.pData[k]; float s12=calDis(p1,p2); float s13=calDis(p1,p3); float s23=calDis(p2,p3); for ( int m=0;m<pc2.pData.size();++m) for ( int n=0;n<pc2.pData.size();++n) for ( int l=0;l<pc2.pData.size();++l) { if (n!=m&&m!=l&&n!=l) { Point _p1=pc2.pData[m]; Point _p2=pc2.pData[n]; Point _p3=pc2.pData[l]; float _s12=calDis(_p1,_p2); float _s13=calDis(_p1,_p3); float _s23=calDis(_p2,_p3); if ( fabs (s12-_s12)<0.45&& fabs (s13-_s13)<0.45&& fabs (s23-_s23)<0.45) { cout<< "pc1....." <<p1.id<< "pc2......" <<_p1.id<<endl; cout<< "pc1....." <<p2.id<< "pc2......" <<_p2.id<<endl; cout<< "pc1....." <<p3.id<< "pc2......" <<_p3.id<<endl; } } } } } int main() { char *file1= "测试点云\\点云Mark0.txt" ; char *file2= "测试点云\\点云Mark1.txt" ; PointCloud pc1,pc2; pc1.readFile(file1); pc2.readFile(file2); PointMatch(pc1,pc2); } |
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原文链接:http://blog.csdn.net/yanglusheng/article/details/52692552