概念
节流函数
间隔固定的时间执行传入的方法
目的是防止函数执行的频率过快,影响性能.常见于跟滚动,鼠标移动事件绑定的功能.
防抖函数
对于接触过硬件的人也许更好理解,硬件按钮按下时,由于用户按住时间的长短不一,会多次触发电流的波动,加一个防抖函数就会只触发一次,防止了无意义的电流波动引起的问题.
按键防反跳(Debounce)为什么要去抖动呢?机械按键在按下时,并非按下就接触的很好,尤其是有簧片的机械开关,会在接触的瞬间反复的开合多次,直到开关状态完全改变。
应用在前端时,常见的场景是,输入框打字动作结束一段时间后再去触发查询/搜索/校验,而不是每打一个字都要去触发,造成无意义的ajax查询等,或者与调整窗口大小绑定的函数,其实只需要在最后窗口大小固定之后再去执行动作.
自己的实现
防抖函数
关键点在于每次触发时都清空延时函数的手柄,只有最后一次触发不会清空手柄,所以最后一次触发会等默认的1s后去执行debounce传入的参数函数f. debounce内部返回的闭包函数,是真正每次被调用触发的函数,不再是原本的f,所以这里的arguments取闭包函数环境变量中的arguments并在执行f时传给f,在setTimeout函数的外面取得.
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let debounce = function (f, interval = 1000) { let handler = null ; return function () { if (handler) { clearTimeout(handler); } let arg = arguments; handler = setTimeout( function () { f.apply( this , arg); clearTimeout(handler); }, interval) } } |
应用:
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let input = document.querySelector( '#input' ); input.addEventListener( 'input' , debounce( function (e) { console.log( "您的输入是" ,e.target.value) })) |
更高级的实现还会考虑到,以leading和trailing作为参数,起始先执行一次函数并消除后面的抖动,还是最后执行一下函数,消除前面的抖动,如同我这里的例子.后面分析loadash的防抖函数时会详细解析.
节流函数
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let throttle = function (f,gap = 300){ let lastCall = 0; return function (){ let now = Date.now(); let ellapsed = now - lastCall; if (ellapsed < gap){ return } f.apply( this ,arguments); lastCall = Date.now(); } } |
闭包函数在不断被调用的期间,去记录离上一次调用间隔的时间,如果间隔时间小于节流设置的时间则直接返回,不去执行真正被包裹的函数f.只有间隔时间大于了节流函数设置的时间gap,才调用f,并更新调用时间.
应用:
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document.addEventListener( 'scroll' , throttle( function (e) { // 判断是否滚动到底部的逻辑 console.log(e,document.documentElement.scrollTop); })); |
lodash源码分析
以上是对节流防抖函数最基础简单的实现,我们接下来分析一下lodash库中节流防抖函数的分析.
节流函数的使用
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$(window).on( 'scroll' , _.debounce(doSomething, 200)); |
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function debounce(func, wait, options) { var lastArgs, lastThis, result, timerId, lastCallTime = 0, lastInvokeTime = 0, leading = false , maxWait = false , trailing = true ; if ( typeof func != 'function' ) { throw new TypeError(FUNC_ERROR_TEXT); } wait = wait || 0; if (isObject(options)) { leading = !!options.leading; maxWait = 'maxWait' in options && Math.max((options.maxWait) || 0, wait); trailing = 'trailing' in options ? !!options.trailing : trailing; } function invokeFunc(time) { var args = lastArgs, thisArg = lastThis; lastArgs = lastThis = undefined; lastInvokeTime = time; result = func.apply(thisArg, args); return result; } function leadingEdge(time) { console.log( "leadingEdge setTimeout" ) // Reset any `maxWait` timer. lastInvokeTime = time; // Start the timer for the trailing edge. timerId = setTimeout(timerExpired, wait); // Invoke the leading edge. return leading ? invokeFunc(time) : result; } function remainingWait(time) { var timeSinceLastCall = time - lastCallTime, timeSinceLastInvoke = time - lastInvokeTime, result = wait - timeSinceLastCall; console.log( "remainingWait" ,result) return maxWait === false ? result : Math.min(result, maxWait - timeSinceLastInvoke); } function shouldInvoke(time) { console.log( "shouldInvoke" ) var timeSinceLastCall = time - lastCallTime, timeSinceLastInvoke = time - lastInvokeTime; console.log( "time" ,time, "lastCallTime" ,lastCallTime, "timeSinceLastCall" ,timeSinceLastCall) console.log( "time" ,time, "lastInvokeTime" ,lastInvokeTime, "timeSinceLastInvoke" ,timeSinceLastInvoke) console.log( "should?" ,(!lastCallTime || (timeSinceLastCall >= wait) || (timeSinceLastCall < 0) || (maxWait !== false && timeSinceLastInvoke >= maxWait))) // Either this is the first call, activity has stopped and we're at the // trailing edge, the system time has gone backwards and we're treating // it as the trailing edge, or we've hit the `maxWait` limit. return (!lastCallTime || (timeSinceLastCall >= wait) || (timeSinceLastCall < 0) || (maxWait !== false && timeSinceLastInvoke >= maxWait)); } function timerExpired() { console.log( "timerExpired" ) var time = Date.now(); if (shouldInvoke(time)) { return trailingEdge(time); } console.log( "Restart the timer." ,time,remainingWait(time)) // Restart the timer. console.log( "timerExpired setTimeout" ) timerId = setTimeout(timerExpired, remainingWait(time)); } function trailingEdge(time) { clearTimeout(timerId); timerId = undefined; // Only invoke if we have `lastArgs` which means `func` has been // debounced at least once. console.log( "trailing" ,trailing, "lastArgs" ,lastArgs) if (trailing && lastArgs) { return invokeFunc(time); } lastArgs = lastThis = undefined; return result; } function cancel() { if (timerId !== undefined) { clearTimeout(timerId); } lastCallTime = lastInvokeTime = 0; lastArgs = lastThis = timerId = undefined; } function flush() { return timerId === undefined ? result : trailingEdge(Date.now()); } function debounced() { var time = Date.now(), isInvoking = shouldInvoke(time); console.log( "time" ,time); console.log( "isInvoking" ,isInvoking); lastArgs = arguments; lastThis = this ; lastCallTime = time; if (isInvoking) { if (timerId === undefined) { return leadingEdge(lastCallTime); } // Handle invocations in a tight loop. clearTimeout(timerId); console.log( "setTimeout" ) timerId = setTimeout(timerExpired, wait); return invokeFunc(lastCallTime); } return result; } debounced.cancel = cancel; debounced.flush = flush; return debounced; } |
ref
https://css-tricks.com/debouncing-throttling-explained-examples/
https://github.com/lodash/lodash/blob/4.7.0/lodash.js#L9840
https://jinlong.github.io/2016/04/24/Debouncing-and-Throttling-Explained-Through-Examples/
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原文链接:https://juejin.im/post/6864556879902130183?utm_source=tuicool&utm_medium=referral