1. pandarallel (pip install )
对于一个带有Pandas DataFrame df的简单用例和一个应用func的函数,只需用parallel_apply替换经典的apply。
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from pandarallel import pandarallel # Initialization pandarallel.initialize() # Standard pandas apply df. apply (func) # Parallel apply df.parallel_apply(func) |
注意,如果不想并行化计算,仍然可以使用经典的apply方法。
另外可以通过在initialize函数中传递progress_bar=True来显示每个工作CPU的一个进度条。
2. joblib (pip install )
https://pypi.python.org/pypi/joblib
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# Embarrassingly parallel helper: to make it easy to write readable parallel code and debug it quickly from math import sqrt from joblib import Parallel, delayed def test(): start = time.time() result1 = Parallel(n_jobs = 1 )(delayed(sqrt)(i * * 2 ) for i in range ( 10000 )) end = time.time() print (end - start) result2 = Parallel(n_jobs = 8 )(delayed(sqrt)(i * * 2 ) for i in range ( 10000 )) end2 = time.time() print (end2 - end) |
-------输出结果----------
0.4434356689453125
0.6346755027770996
3. multiprocessing
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import multiprocessing as mp with mp.Pool(mp.cpu_count()) as pool: df[ 'newcol' ] = pool. map (f, df[ 'col' ]) multiprocessing.cpu_count() |
返回系统的CPU数量。
该数量不同于当前进程可以使用的CPU数量。可用的CPU数量可以由 len(os.sched_getaffinity(0)) 方法获得。
可能引发 NotImplementedError 。
4. 几种方法性能比较
(1)代码
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import sys import time import pandas as pd import multiprocessing as mp from joblib import Parallel, delayed from pandarallel import pandarallel from tqdm import tqdm, tqdm_notebook def get_url_len(url): url_list = url.split( "." ) time.sleep( 0.01 ) # 休眠0.01秒 return len (url_list) def test1(data): """ 不进行任何优化 """ start = time.time() data[ 'len' ] = data[ 'url' ]. apply (get_url_len) end = time.time() cost_time = end - start res = sum (data[ 'len' ]) print ( "res:{}, cost time:{}" . format (res, cost_time)) def test_mp(data): """ 采用mp优化 """ start = time.time() with mp.Pool(mp.cpu_count()) as pool: data[ 'len' ] = pool. map (get_url_len, data[ 'url' ]) end = time.time() cost_time = end - start res = sum (data[ 'len' ]) print ( "test_mp \t res:{}, cost time:{}" . format (res, cost_time)) def test_pandarallel(data): """ 采用pandarallel优化 """ start = time.time() pandarallel.initialize() data[ 'len' ] = data[ 'url' ].parallel_apply(get_url_len) end = time.time() cost_time = end - start res = sum (data[ 'len' ]) print ( "test_pandarallel \t res:{}, cost time:{}" . format (res, cost_time)) def test_delayed(data): """ 采用delayed优化 """ def key_func(subset): subset[ "len" ] = subset[ "url" ]. apply (get_url_len) return subset start = time.time() data_grouped = data.groupby(data.index) # data_grouped 是一个可迭代的对象,那么就可以使用 tqdm 来可视化进度条 results = Parallel(n_jobs = 8 )(delayed(key_func)(group) for name, group in tqdm(data_grouped)) data = pd.concat(results) end = time.time() cost_time = end - start res = sum (data[ 'len' ]) print ( "test_delayed \t res:{}, cost time:{}" . format (res, cost_time)) if __name__ = = '__main__' : columns = [ 'title' , 'url' , 'pub_old' , 'pub_new' ] temp = pd.read_csv( "./input.csv" , names = columns, nrows = 10000 ) data = temp """ for i in range(99): data = data.append(temp) """ print ( len (data)) """ test1(data) test_mp(data) test_pandarallel(data) """ test_delayed(data) |
(2) 结果输出
1k
res:4338, cost time:0.0018074512481689453
test_mp res:4338, cost time:0.2626469135284424
test_pandarallel res:4338, cost time:0.3467681407928467
1w
res:42936, cost time:0.008773326873779297
test_mp res:42936, cost time:0.26111721992492676
test_pandarallel res:42936, cost time:0.33237743377685547
10w
res:426742, cost time:0.07944369316101074
test_mp res:426742, cost time:0.294996976852417
test_pandarallel res:426742, cost time:0.39208269119262695
100w
res:4267420, cost time:0.8074917793273926
test_mp res:4267420, cost time:0.9741342067718506
test_pandarallel res:4267420, cost time:0.6779992580413818
1000w
res:42674200, cost time:8.027287006378174
test_mp res:42674200, cost time:7.751036882400513
test_pandarallel res:42674200, cost time:4.404983282089233
在get_url_len函数里加个sleep语句(模拟复杂逻辑),数据量为1k,运行结果如下:
1k
res:4338, cost time:10.054503679275513
test_mp res:4338, cost time:0.35697126388549805
test_pandarallel res:4338, cost time:0.43415403366088867
test_delayed res:4338, cost time:2.294757843017578
5. 小结
(1)如果数据量比较少,并行处理比单次执行效率更慢;
(2)如果apply的函数逻辑简单,并行处理比单次执行效率更慢。
6. 问题及解决方法
(1)ImportError: This platform lacks a functioning sem_open implementation, therefore, the required synchronization primitives needed will not function, see issue 3770.
https://www.jianshu.com/p/0be1b4b27bde
(2)Linux查看物理CPU个数、核数、逻辑CPU个数
https://lover.blog.csdn.net/article/details/113951192
(3) 进度条的使用
http://www.zzvips.com/article/190442.html
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原文链接:https://blog.csdn.net/jingyi130705008/article/details/113949730