20年初准备投资基金,想爬取基金的业绩数据。
20年基金迎来了爆发式增长,现把代码开源以供参考。
本代码只能实现初步汇总,输出csv文件来保存基金的单位&累计净值,后期仍需要结合统计方法来筛选优质基金。
参考了网上的部分代码,实在不记得出处了,侵删。
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import requests import time import execjs start = time.perf_counter() # 获取所有基金编号 def getAllCode(): url = 'http://fund.eastmoney.com/js/fundcode_search.js' content = requests.get(url) jsContent = execjs. compile (content.text) rawData = jsContent. eval ( 'r' ) allCode = [] for code in rawData: allCode.append(code[ 0 ]) return allCode allCode = getAllCode() del allCode[ 100 : len (allCode)] # print(len(allCode)) # 获取基金编号为fscode的所有信息 def getUrl(fscode): head = 'http://fund.eastmoney.com/pingzhongdata/' tail = '.js?v=' + time.strftime( "%Y%m%d%H%M%S" , time.localtime()) return head + fscode + tail # 获取净值 def getWorth(fscode): content = requests.get(getUrl(fscode)) jsContent = execjs. compile (content.text) name = jsContent. eval ( 'fS_name' ) code = jsContent. eval ( 'fS_code' ) # 单位净值走势 netWorthTrend = jsContent. eval ( 'Data_netWorthTrend' ) # 累计净值走势 ACWorthTrend = jsContent. eval ( 'Data_ACWorthTrend' ) # 近一年收益率 Profit_12month = jsContent. eval ( 'syl_1n' ) netWorth = [] ACWorth = [] for dayWorth in netWorthTrend[:: - 1 ]: netWorth.append(dayWorth[ 'y' ]) for dayACWorth in ACWorthTrend[:: - 1 ]: ACWorth.append(dayACWorth[ 1 ]) print (name, code) return netWorth, ACWorth netWorthFile = open ( './netWorth.csv' , 'w' ) ACWorthFile = open ( './ACWorth.csv' , 'w' ) for code in allCode: try : netWorth, ACWorth = getWorth(code) except : continue if len (netWorth) < = 0 or len (ACWorth) < 0 : # print(code + " empty data") continue netWorthFile.write( "\'" + code + "\'," ) netWorthFile.write( "," .join( list ( map ( str , netWorth)))) netWorthFile.write( "\n" ) ACWorthFile.write( "\'" + code + "\'," ) ACWorthFile.write( "," .join( list ( map ( str , ACWorth)))) ACWorthFile.write( "\n" ) # print("write " + code + " success.") netWorthFile.close() ACWorthFile.close() end = time.perf_counter() print ( 'Running time: %s seconds' % (end - start)) |
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原文链接:https://blog.csdn.net/Coefficient1996/article/details/114360549