mysql中TIMESTAMPDIFF案例详解

1.  Syntax

TIMESTAMPDIFF(unit,begin,end); 根据单位返回时间差,对于传入的begin和end不需要相同的数据结构,可以存在一个为Date一个DateTime

2. Unit

支持的单位有

• MICROSECOND
• SECOND
• MINUTE
• HOUR
• DAY
• WEEK
• MONTH
• QUARTER
• YEAR

3. Example

下面这个例子是对于TIMESTAMPDIFF最基本的用法，

• 3.1 求 2017-01-01 - 2017-02-01 之间有几个月

• 3.2 求 2017-01-01 - 2017-02-01 之间有几天

•  3.3 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:00 之间有几分钟

•  3.4 求 2017-01-01 08: 00:00 - 2017-01-01 08: 55:33 之间有几分钟

•  3.5 对于DAY， MINUTE进行计算DIFF时，会直接将相对应的DAY，MINUTE相减

• 3.6 对于 SECOND 会怎样计算呢

• 3.7 如何求数据库中两个date字段的diff
  • 3.7.1  建表
    ?

    1 2	CREATE TABLE demo (id INT AUTO_INCREMENT PRIMARY KEY, start_time DATE NOT NULL, end_time DATE NOT NULL); Query OK, 0 rows affected (0.10 sec)
  • 3.7.2  添加数据
    ?

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    INSERT INTO demo(start_time, end_time) VALUES('1983-01-01', '1990-01-01'), ('1983-01-01', '1989-06-06'), ('1983-01-01', '1985-03-02'), ('1983-01-01', '1992-05-05'), ('1983-01-01 11:12:11', '1995-12-01');
  • 3.7.3 直接query数据
    ?

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    select * from demo; +----+------------+------------+ | id | start_time | end_time | +----+------------+------------+ | 1 | 1983-01-01 | 1990-01-01 | | 2 | 1983-01-01 | 1989-06-06 | | 3 | 1983-01-01 | 1985-03-02 | | 4 | 1983-01-01 | 1992-05-05 | | 5 | 1983-01-01 | 1995-12-01 | +----+------------+------------+ 5 rows in set (0.00 sec)
  • 3.7.4 计算duration
    ?

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    select *, TIMESTAMPDIFF(YEAR, start_time, end_time) as duration from demo;   +----+------------+------------+----------+ | id | start_time | end_time | duration | +----+------------+------------+----------+ | 1 | 1983-01-01 | 1990-01-01 | 7 | | 2 | 1983-01-01 | 1989-06-06 | 6 | | 3 | 1983-01-01 | 1985-03-02 | 2 | | 4 | 1983-01-01 | 1992-05-05 | 9 | | 5 | 1983-01-01 | 1995-12-01 | 12 | +----+------------+------------+----------+ 5 rows in set (0.00 sec)
  • 3.7.5 其他应用
    ?

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    select *, if(TIMESTAMPDIFF(YEAR, end_time, CURRENT_TIMESTAMP())< 26 ,'< 26','>= 26') as result from demo;   +----+------------+------------+--------+ | id | start_time | end_time | result | +----+------------+------------+--------+ | 1 | 1983-01-01 | 1990-01-01 | >= 26 | | 2 | 1983-01-01 | 1989-06-06 | >= 26 | | 3 | 1983-01-01 | 1985-03-02 | >= 26 | | 4 | 1983-01-01 | 1992-05-05 | < 26 | | 5 | 1983-01-01 | 1995-12-01 | < 26 | +----+------------+------------+--------+ 5 rows in set (0.00 sec)

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原文链接：https://blog.csdn.net/baiyaoliang7445/article/details/102218767