今天填一个坑,俄罗斯方块!!
俄罗斯方块的移动不难实现,但是旋转就不太容易实现,究其原因是因为Python中没有数组这种数据结构,所以不能用矩阵的公式。今天把旋转做出来了,刚好整理一下,把之前的都整合在一起
俄罗斯方块-打印
功能:输入字母,打印俄罗斯方块的*图形
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# 尽可能吧俄罗斯方块放在中间 Tetris = { 'L' : [[ 1 , 1 ], [ 1 , 2 ], [ 1 , 3 ], [ 2 , 3 ]], 'O' : [[ 1 , 1 ], [ 2 , 1 ], [ 1 , 2 ], [ 2 , 2 ]], 'J' : [[ 2 , 1 ], [ 2 , 2 ], [ 1 , 3 ], [ 2 , 3 ]], 'Z' : [[ 1 , 1 ], [ 2 , 1 ], [ 2 , 2 ], [ 3 , 2 ]], 'S' : [[ 1 , 1 ], [ 1 , 2 ], [ 2 , 2 ], [ 2 , 3 ]], 'I' : [[ 1 , 1 ], [ 1 , 2 ], [ 1 , 3 ], [ 1 , 4 ]], 'T' : [[ 1 , 1 ], [ 2 , 1 ], [ 2 , 2 ], [ 3 , 1 ]]} print (Tetris) while True : figure = input ( "请输入俄罗斯方块的形状" ) flag = 0 for i in range ( 0 , 5 ): for j in range ( 0 , 4 ): for li in range ( 0 , len (Tetris[figure])): # Tetris['L'] if j = = Tetris[figure][li][ 0 ] and i = = Tetris[figure][li][ 1 ]: flag = 1 if flag = = 1 : print ( "*" , end = '') else : print ( " " , end = '') flag = 0 print () |
俄罗斯方块-移动
这一版使用了函数+字典
功能:输入字母,打印俄罗斯方块的*图形,输入468可以移动
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# 文件名称:Model-Tetris.PY # 开发工具:PyCharm Tetris = { 'L' : [[ 1 , 1 ], [ 1 , 2 ], [ 1 , 3 ], [ 2 , 3 ]], 'O' : [[ 1 , 1 ], [ 2 , 1 ], [ 1 , 2 ], [ 2 , 2 ]], 'J' : [[ 2 , 1 ], [ 2 , 2 ], [ 1 , 3 ], [ 2 , 3 ]], 'Z' : [[ 1 , 1 ], [ 2 , 1 ], [ 2 , 2 ], [ 3 , 2 ]], 'S' : [[ 1 , 1 ], [ 1 , 2 ], [ 2 , 2 ], [ 2 , 3 ]], 'I' : [[ 1 , 1 ], [ 1 , 2 ], [ 1 , 3 ], [ 1 , 4 ]], 'T' : [[ 1 , 1 ], [ 2 , 1 ], [ 2 , 2 ], [ 3 , 1 ]]} def L_char(char): flag = 0 for i in range ( 0 , 7 ): for j in range ( 0 , 7 ): for li in range ( 0 , len (Tetris[char])): # Tetris['L'] if j = = Tetris[char][li][ 0 ] and i = = Tetris[char][li][ 1 ]: flag = 1 if flag = = 1 : print ( "*" , end = '') else : print ( " " , end = '') flag = 0 print () def move(char, num): if num = = 2 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 1 ] + = 1 if num = = 4 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 0 ] - = 1 if num = = 6 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 0 ] + = 1 if num = = 8 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 1 ] - = 1 |
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# 文件名称:Test-Tetris.PY # 开发工具:PyCharm from Day05 import Model_Tetris if __name__ = = '__main__' : char = input ( "请输入图形:" ) Model_Tetris.L_char(char) while True : num = int ( input ( "请输入移动代码2/4/6/8:" )) if num = = 8 or num = = 2 or num = = 4 or num = = 6 : Model_Tetris.move(char, num) Model_Tetris.L_char(char) else : break |
俄罗斯方块-旋转
主要思想:预定义4X4的坐标转换,旋转式查找字典中的转换坐标,进行相应的替换
功能:输入字母,打印俄罗斯方块的*图形,输入468可以移动,输入5可以旋转
废话不多说,直接给出代码:
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#!/usr/bin/python # _*_coding:utf-8_*_ # 开发人员:zys # 开发时间:2021/4/16 16:50 # 文件名称:Test-Tetris.PY # 开发工具:PyCharm import random from Day06.test1 import Model_Tetris if __name__ = = '__main__' : # 随机生成方法 # Character = "LOJSZIT" # char = random.choice(Character) char = "L" Model_Tetris.L_char(char) while True : num = int ( input ( "请输入移动代码4/5/6/8:" )) # 5是旋转 if num = = 8 or num = = 4 or num = = 6 : Model_Tetris.move(char, num) Model_Tetris.L_char(char) elif num = = 5 : Model_Tetris.revolve(char) Model_Tetris.L_char(char) else : break |
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#!/usr/bin/python # _*_coding:utf-8_*_ # 开发人员:zys # 开发时间:2021/4/16 16:36 # 文件名称:Model-Tetris.PY # 开发工具:PyCharm Tetris = { 'L' : [[ 1 , 1 ], [ 1 , 2 ], [ 1 , 3 ], [ 2 , 3 ]], 'O' : [[ 1 , 1 ], [ 1 , 2 ], [ 2 , 1 ], [ 2 , 2 ]], 'J' : [[ 1 , 2 ], [ 2 , 2 ], [ 3 , 1 ], [ 3 , 2 ]], 'Z' : [[ 1 , 1 ], [ 1 , 2 ], [ 2 , 2 ], [ 2 , 3 ]], 'S' : [[ 1 , 1 ], [ 2 , 1 ], [ 2 , 2 ], [ 3 , 2 ]], 'I' : [[ 1 , 1 ], [ 2 , 1 ], [ 3 , 1 ], [ 4 , 1 ]], 'T' : [[ 1 , 1 ], [ 1 , 2 ], [ 2 , 2 ], [ 1 , 3 ]]} # 4*4旋转 '''这里补充一个知识点: 字典中的key是不可变的,所以不能用list作为字典的key, 因为list可以修改,这里采用了元组作为key,指明不可改变, 后面地址查值的时候需要进行类型转换。''' rotateDict = {( 1 , 1 ): [ 4 , 1 ], ( 1 , 2 ): [ 3 , 1 ], ( 1 , 3 ): [ 2 , 1 ], ( 1 , 4 ): [ 1 , 1 ], ( 2 , 1 ): [ 4 , 2 ], ( 3 , 1 ): [ 4 , 3 ], ( 4 , 1 ): [ 4 , 4 ], ( 4 , 2 ): [ 3 , 4 ], ( 4 , 3 ): [ 2 , 4 ], ( 4 , 4 ): [ 1 , 4 ], ( 3 , 4 ): [ 1 , 3 ], ( 2 , 4 ): [ 1 , 2 ], ( 2 , 2 ): [ 3 , 2 ], ( 3 , 2 ): [ 3 , 3 ], ( 3 , 3 ): [ 2 , 3 ], ( 2 , 3 ): [ 2 , 2 ]} def L_char(char): flag = 0 for i in range ( 0 , 5 ): for j in range ( 0 , 5 ): for li in range ( 0 , len (Tetris[char])): # Tetris['L'] if j = = Tetris[char][li][ 0 ] and i = = Tetris[char][li][ 1 ]: flag = 1 if flag = = 1 : print ( "*" , end = '') else : print ( " " , end = '') flag = 0 print () def move(char, num): if num = = 2 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 1 ] + = 1 if num = = 4 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 0 ] - = 1 if num = = 6 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 0 ] + = 1 if num = = 8 : for li in range ( 0 , len (Tetris[char])): Tetris[char][li][ 1 ] - = 1 def revolve(char): newTetris = [] # 新的list for i in range ( len (Tetris[char])): newTetris.append(rotateDict[ tuple (Tetris[char][i])]) # 对应坐标添加到新的坐标 Tetris[char] = newTetris |
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原文链接:https://blog.csdn.net/to_upper/article/details/115750393