本文实例为大家分享了C语言实现简单的扫雷小游戏的具体代码，供大家参考，具体内容如下
首先来规划一下扫雷游戏实现的几个步骤：
初始化棋盘：二维数组的遍历及赋值
为了后续代码的简洁方便，我们用'0'来初始化
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void InitBoard(char board[ROWS][COLS], int rows, int cols, char set){ int i = 0; int j = 0; for (i = 0; i < rows; i++) { for (j = 0; j < cols; j++) { board[i][j] = set; } }} |
布置雷的信息：应用随机函数进行赋值
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void SetMine(char mine[ROWS][COLS], int row, int col){ int count = EASY_COUNT; while (count) { int x = rand() % row + 1; int y = rand() % col + 1; if (mine[x][y] == '0') { mine[x][y] = '1'; count--; } }} |
排查雷：
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void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){ int x = 0; int y = 0; int win = 0; while (win<row*col- EASY_COUNT) { printf("请输入要排查的坐标->"); scanf("%d %d", &x, &y); if (x >= 1 && x <= row && y >= 1 && y <= col) { if (mine[x][y] == '1') { printf("很遗憾你被炸死了\n"); DisplayBoard(mine, row, col); break; } else { //计算x,y坐标周围有几个雷 int n=get_mine_count(mine, x, y); show[x][y] = n + '0'; DisplayBoard(show, row, col); win++; } } else printf("输入坐标错误，请重新输入\n"); } if (win == row * col - EASY_COUNT) { printf("恭喜你，排雷成功\n"); DisplayBoard(mine, row, col); }} |
下面是游戏实现的完整代码，依旧是分为了3个版块，为了更好的管理代码，提高代码的可读性和可移植性
game2.h
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#include <stdio.h>#include <time.h>#include <stdlib.h>#define ROW 9#define COL 9#define EASY_COUNT 10#define ROWS ROW+2#define COLS COL+2//初始化棋盘void InitBoard(char board[ROWS][COLS], int rows, int cols, char set);//打印棋盘void DisplayBoard(char board[ROWS][COLS], int row, int col);//布置雷void SetMine(char mine[ROWS][COLS], int row, int col);//排查雷void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col); |
game2.c
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#include "game2.h"void InitBoard(char board[ROWS][COLS], int rows, int cols, char set){ int i = 0; int j = 0; for (i = 0; i < rows; i++) { for (j = 0; j < cols; j++) { board[i][j] = set; } }}void DisplayBoard(char board[ROWS][COLS], int row, int col){ int i = 0; int j = 0; for (i = 0; i <= col; i++) { printf("%d ", i); } printf("\n"); for (i = 1; i <= row; i++) { printf("%d ", i); for (j = 1; j <= col; j++) { printf("%c ", board[i][j]); } printf("\n"); }}//布置雷void SetMine(char mine[ROWS][COLS], int row, int col){ int count = EASY_COUNT; while (count) { int x = rand() % row + 1; int y = rand() % col + 1; if (mine[x][y] == '0') { mine[x][y] = '1'; count--; } }}static int get_mine_count(char mine[ROWS][COLS], int x, int y){ return mine[x - 1][y] + mine[x - 1][y - 1] + mine[x][y - 1] + mine[x + 1][y] + mine[x + 1][y + 1] + mine[x][y + 1] + mine[x - 1][y + 1]+ mine[x+1][y-1]-8*'0';}void FindMine(char mine[ROWS][COLS], char show[ROWS][COLS], int row, int col){ int x = 0; int y = 0; int win = 0; while (win<row*col- EASY_COUNT) { printf("请输入要排查的坐标->"); scanf("%d %d", &x, &y); if (x >= 1 && x <= row && y >= 1 && y <= col) { if (mine[x][y] == '1') { printf("很遗憾你被炸死了\n"); DisplayBoard(mine, row, col); break; } else { //计算x,y坐标周围有几个雷 int n=get_mine_count(mine, x, y); show[x][y] = n + '0'; DisplayBoard(show, row, col); win++; } } else printf("输入坐标错误，请重新输入\n"); } if (win == row * col - EASY_COUNT) { printf("恭喜你，排雷成功\n"); DisplayBoard(mine, row, col); }} |
test.c
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#include "game2.h"void menu(){ printf("**************************\n"); printf("******* 1.play *******\n"); printf("******* 0.exit *******\n"); printf("**************************\n");}void game(){ //创建数组 char mine[ROWS][COLS] = { 0 };//存放布置好的雷的信息 char show[ROWS][COLS] = { 0 };//存放排查出的雷的信息 //初始化mine数组全部为‘0' InitBoard(mine, ROWS, COLS, '0'); //初始化show数组全部为‘0' InitBoard(show, ROWS, COLS, '*'); //打印棋盘 //DisplayBoard(mine, ROW, COL); //布置雷 SetMine(mine, ROW, COL); DisplayBoard(show, ROW, COL); //DisplayBoard(mine, ROW, COL); //排查雷 FindMine(mine, show, ROW, COL);}void test(){ int input = 0; srand((unsigned int)time(NULL)); do { menu(); printf("请选择->"); scanf("%d", &input); switch (input) { case 1: game(); break; case 0: printf("退出游戏\n"); break; default: printf("选择错误\n"); break; } } while (input);}int main(){ test(); return 0;} |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/weixin_54175406/article/details/121442177
