在某些情况下熟悉SQL Server 通配符的使用可以帮助我们简单的解决很多问题。
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--使用_运算符查找Person表中以an结尾的三字母名字 USEAdventureWorks2012; GO SELECT FirstName, LastName FROM Person.Person WHERE FirstName LIKE '_an' ORDER BY FirstName; ---使用[^]运算符在Contact表中查找所有名字以Al开头且第三个字母不是字母a的人 USEAdventureWorks2012; GO SELECT FirstName, LastName FROM Person.Person WHERE FirstName LIKE 'Al[^a]%' ORDER BY FirstName; ---使用[]运算符查找其地址中有四位邮政编码的所有Adventure Works雇员的ID和姓名 USEAdventureWorks2012; GO SELECT e.BusinessEntityID, p.FirstName, p.LastName, a.PostalCode FROMHumanResources.EmployeeAS e INNER JOIN Person.PersonAS pON e.BusinessEntityID= p.BusinessEntityID INNER JOIN Person.BusinessEntityAddressAS eaON e.BusinessEntityID=ea.BusinessEntityID INNER JOIN Person.AddressAS aON a.AddressID= ea.AddressID WHERE a.PostalCodeLIKE '[0-9][0-9][0-9][0-9]' ; |
结果集:
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EmployeeID FirstName LastName PostalCode ---------- --------- --------- ---------- 290 Lynn Tsoflias 3000 |
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--将一张表中名字为中英文的区分出来(借鉴论坛中的代码) create table tb(namenvarchar(20)) insert into tbvalues( 'kevin' ) insert into tbvalues( 'kevin刘' ) insert into tbvalues( '刘' ) select *, 'Eng' from tbwherepatindex( '%[a-z]%' , name )>0and(patindex( '%[吖-坐]%' , name )=0) union all select *, 'CN' from tbwherepatindex( '%[吖-坐]%' , name )>0andpatindex( '%[a-z]%' , name )=0 union all select *, 'Eng&CN' from tbwhere(patindex( '%[吖-坐]%' , name )>0)andpatindex( '%[a-z]%' , name )>0 |
结果集:
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name -------------------- ------ kevin Eng 刘 CN kevin刘 Eng&CN (3 row(s) affected) |