在我的印象里面进制互相转换确实是很常见的问题,所以在Python中,自然也少不了把下面这些代码收为util。
这是从网上搜索的一篇也的还可以的Python进制转换,经过验证可以使用。下面贴出它的实现代码:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
|
#!/usr/bin/env python # -*- coding: utf-8 -*- # 2/10/16 base trans. wrote by srcdog on 20th, April, 2009 # ld elements in base 2, 10, 16. import os,sys # global definition # base = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F] base = [ str (x) for x in range ( 10 )] + [ chr (x) for x in range ( ord ( 'A' ), ord ( 'A' ) + 6 )] # bin2dec # 二进制 to 十进制: int(str,n=10) def bin2dec(string_num): return str ( int (string_num, 2 )) # hex2dec # 十六进制 to 十进制 def hex2dec(string_num): return str ( int (string_num.upper(), 16 )) # dec2bin # 十进制 to 二进制: bin() def dec2bin(string_num): num = int (string_num) mid = [] while True : if num = = 0 : break num,rem = divmod (num, 2 ) mid.append(base[rem]) return ''.join([ str (x) for x in mid[:: - 1 ]]) # dec2hex # 十进制 to 八进制: oct() # 十进制 to 十六进制: hex() def dec2hex(string_num): num = int (string_num) mid = [] while True : if num = = 0 : break num,rem = divmod (num, 16 ) mid.append(base[rem]) return ''.join([ str (x) for x in mid[:: - 1 ]]) # hex2tobin # 十六进制 to 二进制: bin(int(str,16)) def hex2bin(string_num): return dec2bin(hex2dec(string_num.upper())) # bin2hex # 二进制 to 十六进制: hex(int(str,2)) def bin2hex(string_num): return dec2hex(bin2dec(string_num)) |