本文实例讲述了python比较2个xml内容的方法。分享给大家供大家参考。具体分析如下:
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from xml.etree import ElementTree OK = True main_pid = 10000 loop_depth = 0 def compare_xml(left, right, key_info = '.' ): global loop_depth loop_depth + = 1 if loop_depth = = 1 : print if left.tag ! = right.tag: print_diff(main_pid, key_info, 'difftag' , left.tag, right.tag) return if left.text ! = right.text: print_diff(main_pid, key_info, 'difftext' , left.text, right.text) return leftitems = dict (left.items()) rightitems = dict (right.items()) for k,v in leftitems.items(): if k not in rightitems: s = '%s/%s' % (key_info, left.tag) print_diff(main_pid, s, 'lostattr' , k, "") for k,v in rightitems.items(): if k not in leftitems: s = '%s/%s' % (key_info, right.tag) print_diff(main_pid, s, 'extraattr' , "", k) leftnodes = left.getchildren() rightnodes = right.getchildren() leftlen = len (leftnodes) rightlen = len (rightnodes) if leftlen ! = rightlen: s = '%s/%s' % (key_info, right.tag) print_diff(main_pid, s, 'difflen' , leftlen, rightlen) return l = leftlen<rightlen and leftlen or rightlen d = {} for i in xrange (l): node = leftnodes[i] if node.tag not in d: d[node.tag] = 1 tag = node.tag else : tag = node.tag + str (d[node.tag]) d[node.tag] + = 1 s = '%s/%s' % (key_info, tag) compare_xml(leftnodes[i], rightnodes[i], s) def print_diff(main_pid, key_info, msg, base_type, test_type): global OK info = u '[ %-5s ] %s -> %-40s [ %s != %s ]' % (msg.upper(), main_pid, key_info.strip( './' ), base_type, test_type) print info.encode( 'gbk' ) OK = False |
调用:
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if __name__ = = '__main__' : s1 = '''''<?xml version="1.0" encoding="UTF-8"?> \ <employees> \ <employee id = '1'> \ <name>linux</name>\ <age>30</age>\ </employee>\ <employee id = '2'> \ <name>windows</name>\ <age>20</age>\ </employee>\ </employees>''' s2 = '''''<?xml version="1.0" encoding="UTF-8"?> \ <employees> \ <employee id = '3'> \ <name>windows</name>\ <age>20</age>\ </employee>\ <employee id = '4'> \ <name>linux</name>\ <age>30</age>\ </employee>\ </employees>''' lroot = ElementTree.fromstring(s1) rroot = ElementTree.fromstring(s2) compare_xml(lroot, rroot) |
希望本文所述对大家的Python程序设计有所帮助。