本文实例讲述了python实现提取百度搜索结果的方法。分享给大家供大家参考。具体实现方法如下:
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# coding=utf8 import urllib2 import string import urllib import re import random #设置多个user_agents,防止百度限制IP user_agents = [ 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:23.0) Gecko/20130406 Firefox/23.0' , \ 'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:18.0) Gecko/20100101 Firefox/18.0' , \ 'Mozilla / 5.0 (Windows; U; Windows NT 6.1 ; en - US) AppleWebKit / 533 + \ (KHTML, like Gecko) Element Browser 5.0 ', \ 'IBM WebExplorer /v0.94' , 'Galaxy/1.0 [en] (Mac OS X 10.5.6; U; en)' , \ 'Mozilla/5.0 (compatible; MSIE 10.0; Windows NT 6.1; WOW64; Trident/6.0)' , \ 'Opera/9.80 (Windows NT 6.0) Presto/2.12.388 Version/12.14' , \ 'Mozilla / 5.0 (iPad; CPU OS 6_0 like Mac OS X) AppleWebKit / 536.26 (KHTML, like Gecko) \ Version / 6.0 Mobile / 10A5355d Safari / 8536.25 ', \ 'Mozilla / 5.0 (Windows NT 6.1 ) AppleWebKit / 537.36 (KHTML, like Gecko) \ Chrome / 28.0 . 1468.0 Safari / 537.36 ', \ 'Mozilla/5.0 (compatible; MSIE 9.0; Windows NT 6.0; Trident/5.0; TheWorld)' ] def baidu_search(keyword,pn): p = { 'wd' : keyword} res = urllib2.urlopen(( "http://www.baidu.com/s?" + urllib.urlencode(p) + "&pn={0}&cl=3&rn=100" ). format (pn)) html = res.read() return html def getList(regex,text): arr = [] res = re.findall(regex, text) if res: for r in res: arr.append(r) return arr def getMatch(regex,text): res = re.findall(regex, text) if res: return res[ 0 ] return "" def clearTag(text): p = re. compile (u '<[^>]+>' ) retval = p.sub("",text) return retval def geturl(keyword): for page in range ( 10 ): pn = page * 100 + 1 html = baidu_search(keyword,pn) content = unicode (html, 'utf-8' , 'ignore' ) arrList = getList(u "<table.*?class=\"result\".*?>.*?<\/a>" , content) for item in arrList: regex = u "<h3.*?class=\"t\".*?><a.*?href=\"(.*?)\".*?>(.*?)<\/a>" link = getMatch(regex,item) url = link[ 0 ] #获取标题 #title = clearTag(link[1]).encode('utf8') try : domain = urllib2.Request(url) r = random.randint( 0 , 11 ) domain.add_header( 'User-agent' , user_agents[r]) domain.add_header( 'connection' , 'keep-alive' ) response = urllib2.urlopen(domain) uri = response.geturl() print uri except : continue if __name__ = = '__main__' : geturl( 'python' ) |
希望本文所述对大家的Python程序设计有所帮助。