Python实现的简单算术游戏实例_Python

本文实例讲述了Python实现的简单算术游戏。分享给大家供大家参考。具体实现方法如下：

									#!/usr/bin/env python

									from operator import add, sub 

									from random import randint, choice

									ops = {'+': add, '-':sub}

									#定义一个字典

									MAXTRIES = 2

									def doprob():

									  op = choice('+-')

									  #用choice从'+-'中随意选择操作符 

									  nums = [randint(1,10) for i in range(2)]

									  #用randint(1,10)随机生成一个1到10的数,随机两次使用range(2) 

									  nums.sort(reverse=True)

									  #按升序排序

									  ans = ops[op](*nums)

									  #利用函数

									  pr = '%d %s %d = ' % (nums[0], op, nums[1])

									  oops = 0

									  #oops用来计算failure测试,当三次时自动给出答案

									  while True:

									    try:

									      if int(raw_input(pr)) == ans:

									        print 'correct'

									        break

									      if oops == MAXTRIES:

									        print 'answer\n %s%d' % (pr, ans)

									        break

									      else:

									        print 'incorrect... try again'

									        oops += 1

									    except (KeyboardInterrupt, EOFError, ValueError):

									      print 'invalid ipnut... try again'

									def main():

									  while True:

									    doprob()

									    try:

									      opt = raw_input('Again? [y]').lower()

									      if opt and opt[0] == 'n':

									        break

									    except (KeyboardInterrupt, EOFError):

									      break

									if __name__ == '__main__':

									  main()

运行结果如下：

									8 - 1 = 7

									correct

									Again? [y]y

									7 - 1 = 6

									correct

									Again? [y]y

									9 + 4 = 0

									incorrect... try again

									9 + 4 =

希望本文所述对大家的Python程序设计有所帮助。

Python实现的简单算术游戏实例

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