行和列的位置都在以下三个列表中的一列中,则对应位置为1,其余位置全为0
——[7-56,239-327,438-454,522-556,574-586]
——[57-85,96-112,221-238]
——[113-220,328-437,455-521,557-573]
代码实现
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def generateMaskBasedOnDom(dom_path, length): """ :param dom_path: this is a file path, which contains the following information: [7-56,239-327,438-454,522-556,574-586][57-85,96-112,221-238][113-220,328-437,455-521,557-573] each [...] means one domain :param length: this is the length of this protein :return: the mask matrix with size length x length, 1 means inner domain residue pair, otherwise 0 """ # 读取文件 with open (dom_path, "r" , encoding = "utf-8" ) as file : contents = file .readlines() # 获得mask位置数据 list0 = [] list1 = [] list2 = [] for list_idx, content in enumerate (contents): num_range_list = content.strip()[ 1 : - 1 ].split( "," ) for num_range in num_range_list: start_num = int (num_range.split( "-" )[ 0 ]) end_num = int (num_range.split( "-" )[ 1 ]) for num in range (start_num, end_num + 1 ): if list_idx = = 0 : list0.append(num) elif list_idx = = 1 : list1.append(num) else : list2.append(num) mask = np.zeros((length, length)) # 遍历矩阵每个元素 for row in range (mask.shape[ 0 ]): for col in range (mask.shape[ 1 ]): if (row in list0 and col in list0) or (row in list1 and col in list1) or (row in list2 and col in list2): mask[row][col] = 1 return mask if __name__ = = "__main__" : # if no dom file ,please get dom file first with open ( "dom.txt" , "w" , encoding = "utf-8" ) as f: f.write( "[7-56,239-327,438-454,522-556,574-586]" + "\n" + "[57-85,96-112,221-238]" + "\n" + "[113-220,328-437,455-521,557-573]" ) file_path = "./dom.txt" protein_length = 1000 # mask_matrix size mask_matrix = generateMaskBasedOnDom(file_path, protein_length) print ( "*************Generate Mask Matrix Successful!*************" ) # 随机测试几组 print (mask_matrix[ 7 ][ 56 ]) # 1 print (mask_matrix[ 7 ][ 239 ]) # 1 print (mask_matrix[ 8 ][ 57 ]) # 0 print (mask_matrix[ 57 ][ 95 ]) # 0 print (mask_matrix[ 113 ][ 573 ]) # 1 |
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原文链接:https://blog.csdn.net/weixin_44912159/article/details/107395081