本文实例为大家分享了C语言编写五子棋游戏的具体代码，供大家参考，具体内容如下
一、构建棋盘
首先可以用一个二维数组来构建棋盘，下标表示位置，内容表示黑子白子或者空位。当数组内容为1时，该位置为白字，当数组为0时，该位置为白子，空位输出+
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int w[11][11], flag = 0; int a, b; for (int k = 0; k < 11; k++) printf("第%d列\t", k); printf("\n"); for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (w[i][j] == 0) printf("黑\t"); else if (w[i][j] == 1) printf("白\t"); else printf("+\t"); } printf("第%d行\n\n", i); } |
二、判断位置超范围与错误输入
当输入的棋子坐标超出范围或者该位置已经存在棋子，则再次输入棋子坐标。其中flag作为标志作为判别黑手白手的标志。
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if (flag == 0) { printf("黑色下棋\n"); scanf("%d %d", &a, &b); while (a < 0 || a>10 || b < 0 || b>10) { printf("此位置超出范围，请重新输入："); scanf("%d %d", &a, &b); } while (w[a][b] == 0 || w[a][b] == 1) { printf("此位置已有棋子，请重新输入："); scanf("%d %d", &a, &b); } flag = 1; w[a][b] = 0; } else { printf("白色下棋\n"); scanf("%d %d", &a, &b); while (a < 0 || a>10 || b < 0 || b>10) { printf("此位置超出范围，请重新输入："); scanf("%d %d", &a, &b); } while (w[a][b] == 0 || w[a][b] == 1) { printf("此位置已有棋子，请重新输入："); scanf("%d %d", &a, &b); } |
三、判断胜负
在五子棋中，出现五个棋子排成一排或者一列或者斜排即可判为胜出。每当落下一个棋子，对该棋子前后上下斜排五个棋子进行判别，超过五个连续的一样颜色的棋子则胜出。
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int A = 1, B = 1, jieguo = 0, C = 1, D = 1; int x = 1, y = 1, m = 1, n = 1; if (w[a][b] == 1) { for (int i = 1; i < 5; i++) { if (w[a][b + i] == 1) A++; else break; } for (int i = 1; i < 5; i++) { if (w[a][b - i] == 1) A++; else break; } for (int i = 1; i < 5; i++) { if (w[a+i][b] == 1) C++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b] == 1) C++; else break; } if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志 else { for (int i = 1; i < 5; i++) { if (w[a+i][b + i] == 1) x++; else break; } for (int i = 1; i < 5; i++) { if (w[a-i][b - i] == 1) x++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b-i] == 1) y++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b+i] == 1) y++; else break; } if (x > 4 || y > 4) jieguo = 1; } } if (w[a][b] == 0) { for (int i = 1; i < 5; i++) { if (w[a][b + i] == 0) B++; else break; } for (int i = 1; i < 5; i++) { if (w[a][b - i] == 0) B++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b] == 0) D++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b] == 0) D++; else break; } if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志 else { for (int i = 1; i < 5; i++) { if (w[a + i][b + i] == 0) m++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b - i] == 0) m++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b - i] == 0) n++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b + i] == 0) n++; else break; } if (m > 4 || n > 4) jieguo = 2; } } |
程序完成
四、演示结果
五、源代码
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int main() { int w[11][11], flag = 0; int a, b; while (1) { if (flag == 0) { printf("黑色下棋\n"); scanf("%d %d", &a, &b); while (a < 0 || a>10 || b < 0 || b>10) { printf("此位置超出范围，请重新输入："); scanf("%d %d", &a, &b); } while (w[a][b] == 0 || w[a][b] == 1) { printf("此位置已有棋子，请重新输入："); scanf("%d %d", &a, &b); } flag = 1; w[a][b] = 0; } else { printf("白色下棋\n"); scanf("%d %d", &a, &b); while (a < 0 || a>10 || b < 0 || b>10) { printf("此位置超出范围，请重新输入："); scanf("%d %d", &a, &b); } while (w[a][b] == 0 || w[a][b] == 1) { printf("此位置已有棋子，请重新输入："); scanf("%d %d", &a, &b); } flag = 0; w[a][b] = 1; } int A = 1, B = 1, jieguo = 0, C = 1, D = 1; int x = 1, y = 1, m = 1, n = 1; if (w[a][b] == 1) { for (int i = 1; i < 5; i++) { if (w[a][b + i] == 1) A++; else break; } for (int i = 1; i < 5; i++) { if (w[a][b - i] == 1) A++; else break; } for (int i = 1; i < 5; i++) { if (w[a+i][b] == 1) C++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b] == 1) C++; else break; } if (A > 4 || C > 4) jieguo = 1;//白棋胜利标志 else { for (int i = 1; i < 5; i++) { if (w[a+i][b + i] == 1) x++; else break; } for (int i = 1; i < 5; i++) { if (w[a-i][b - i] == 1) x++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b-i] == 1) y++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b+i] == 1) y++; else break; } if (x > 4 || y > 4) jieguo = 1; } } if (w[a][b] == 0) { for (int i = 1; i < 5; i++) { if (w[a][b + i] == 0) B++; else break; } for (int i = 1; i < 5; i++) { if (w[a][b - i] == 0) B++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b] == 0) D++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b] == 0) D++; else break; } if (B > 4 || D > 4) jieguo = 2;//黑棋胜利标志 else { for (int i = 1; i < 5; i++) { if (w[a + i][b + i] == 0) m++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b - i] == 0) m++; else break; } for (int i = 1; i < 5; i++) { if (w[a + i][b - i] == 0) n++; else break; } for (int i = 1; i < 5; i++) { if (w[a - i][b + i] == 0) n++; else break; } if (m > 4 || n > 4) jieguo = 2; } } for (int k = 0; k < 11; k++) printf("第%d列\t", k); printf("\n"); for (int i = 0; i < 11; i++) { for (int j = 0; j < 11; j++) { if (w[i][j] == 0) printf("黑\t"); else if (w[i][j] == 1) printf("白\t"); else printf("+\t"); } printf("第%d行\n\n", i); } if (jieguo == 1) { printf("白棋胜利"); break; } if (jieguo == 2) { printf("黑棋胜利"); break; } } return 0;} |
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原文链接：https://blog.csdn.net/weixin_46265516/article/details/104171447
