python字符串过滤性能比较5种方法_Python

python 字符串过滤性能比较5种方法比较

总共比较5种方法。直接看代码：

									import random

									import time

									import os

									import string

									base = string.digits+string.punctuation

									total = 100000

									def loop(ss):

									  """循环"""

									  rt = ''

									  for c in ss:

									    if c in '0123456789':

									      rt = rt + c

									  return rt

									def regular(ss):

									  """正则表达式"""

									  import re

									  rt = re.sub(r'\D', '', ss)

									  return rt

									def filter_mt(ss):

									  """函数式"""

									  return filter(lambda c:c.isdigit(), ss)

									def list_com(ss):

									  """列表生成式"""

									  isdigit = {'0': 1, '1': 1, '2': 1, '3': 1, '4': 1,

									            '5':1, '6':1, '7':1, '8':1, '9':1}.has_key

									  return ''.join([x for x in ss if isdigit(x)])

									def str_tran(ss):

									  """string.translate()"""

									  table = string.maketrans('', '')

									  ss = ss.translate(table,string.punctuation)

									  return ss

									if __name__ == '__main__':

									  lst = []

									  for i in xrange(total):

									    num = random.randrange(10, 50)

									    ss = ''

									    for j in xrange(num):

									      ss = ss + random.choice(base)

									    lst.append(ss)

									  s1 = time.time()

									  map(loop,lst)

									  print "loop: ",time.time() - s1

									  print '*'*20

									  s1 = time.time()

									  map(regular, lst)

									  print "regular: ", time.time() - s1

									  print '*' * 20

									  s1 = time.time()

									  map(str_tran, lst)

									  print "str_tran: ", time.time() - s1

									  print '*' * 20

									  s1 = time.time()

									  map(filter_mt, lst)

									  print "filter_mt: ", time.time() - s1

									  print '*' * 20

									  s1 = time.time()

									  map(list_com, lst)

									  print "list_com: ", time.time() - s1

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python字符串过滤性能比较5种方法

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