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# -*- coding: utf-8 -*- '''获取当前日期前后N天或N月的日期''' from time import strftime, localtime from datetime import timedelta, date import calendar year = strftime( "%Y" ,localtime()) mon = strftime( "%m" ,localtime()) day = strftime( "%d" ,localtime()) hour = strftime( "%H" ,localtime()) min = strftime( "%M" ,localtime()) sec = strftime( "%S" ,localtime()) def today(): ''''' get today,date format="YYYY-MM-DD" ''' '' return date.today() def todaystr(): ''' get date string, date format="YYYYMMDD" ''' return year + mon + day def datetime(): ''''' get datetime,format="YYYY-MM-DD HH:MM:SS" ''' return strftime( "%Y-%m-%d %H:%M:%S" ,localtime()) def datetimestr(): ''''' get datetime string date format="YYYYMMDDHHMMSS" ''' return year + mon + day + hour + min + sec def get_day_of_day(n = 0 ): ''''' if n>=0,date is larger than today if n<0,date is less than today date format = "YYYY-MM-DD" ''' if (n< 0 ): n = abs (n) return date.today() - timedelta(days = n) else : return date.today() + timedelta(days = n) def get_days_of_month(year,mon): ''''' get days of month ''' return calendar.monthrange(year, mon)[ 1 ] def get_firstday_of_month(year,mon): ''''' get the first day of month date format = "YYYY-MM-DD" ''' days = "01" if ( int (mon)< 10 ): mon = "0" + str ( int (mon)) arr = (year,mon,days) return "-" .join( "%s" % i for i in arr) def get_lastday_of_month(year,mon): ''''' get the last day of month date format = "YYYY-MM-DD" ''' days = calendar.monthrange(year, mon)[ 1 ] mon = addzero(mon) arr = (year,mon,days) return "-" .join( "%s" % i for i in arr) def get_firstday_month(n = 0 ): ''''' get the first day of month from today n is how many months ''' (y,m,d) = getyearandmonth(n) d = "01" arr = (y,m,d) return "-" .join( "%s" % i for i in arr) def get_lastday_month(n = 0 ): ''''' get the last day of month from today n is how many months ''' return "-" .join( "%s" % i for i in getyearandmonth(n)) def getyearandmonth(n = 0 ): ''''' get the year,month,days from today befor or after n months ''' thisyear = int (year) thismon = int (mon) totalmon = thismon + n if (n> = 0 ): if (totalmon< = 12 ): days = str (get_days_of_month(thisyear,totalmon)) totalmon = addzero(totalmon) return (year,totalmon,days) else : i = totalmon / 12 j = totalmon % 12 if (j = = 0 ): i - = 1 j = 12 thisyear + = i days = str (get_days_of_month(thisyear,j)) j = addzero(j) return ( str (thisyear), str (j),days) else : if ((totalmon> 0 ) and (totalmon< 12 )): days = str (get_days_of_month(thisyear,totalmon)) totalmon = addzero(totalmon) return (year,totalmon,days) else : i = totalmon / 12 j = totalmon % 12 if (j = = 0 ): i - = 1 j = 12 thisyear + = i days = str (get_days_of_month(thisyear,j)) j = addzero(j) return ( str (thisyear), str (j),days) def addzero(n): ''''' add 0 before 0-9 return 01-09 ''' nabs = abs ( int (n)) if (nabs< 10 ): return "0" + str (nabs) else : return nabs def get_today_month(n = 0 ): ''''' 获取当前日期前后N月的日期 if n>0, 获取当前日期前N月的日期 if n<0, 获取当前日期后N月的日期 date format = "YYYY-MM-DD" ''' (y,m,d) = getyearandmonth(n) arr = (y,m,d) if ( int (day)< int (d)): arr = (y,m,day) return "-" .join( "%s" % i for i in arr) if __name__ = = "__main__" : print today() print todaystr() print datetime() print datetimestr() print get_day_of_day( 20 ) print get_day_of_day( - 3 ) print get_today_month( - 3 ) print get_today_month( 3 ) |
这篇关于python 日期操作类的文章就介绍到这,里面涉及了python日期操作的一些基础知识。
原文链接:https://blog.csdn.net/haojianxiang/article/details/78533819