本文实例为大家分享了C语言实现三子棋的具体代码，供大家参考，具体内容如下
效果如下：
代码实现：
头文件部分
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#pragma once#include <stdio.h>#include <stdlib.h>#include <time.h>#define ROW 3#define COL 3//函数声明void Initboard(char board[ROW][COL], int row, int col);void Displayboard(char board[ROW][COL], int row, int col);Player(char board[ROW][COL], int row, int col);Computer(char board[ROW][COL], int row, int col);char Judge(char board[ROW][COL], int row, int col); |
函数部分
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#include "game.h"void Initboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (i = 0; i < row; i++) for (j = 0; j < col; j++) board[i][j] = ' ';}//棋盘// x | x | x //---|---|---// x | x | x //---|---|---// x | x | x void Displayboard(char board[ROW][COL], int row, int col){ int i = 0; int j = 0; for (i = 0; i < row; i++) { //打印一行数据 for (j = 0; j < col; j++) { printf(" %c ", board[i][j]); if (j < col - 1) printf("|"); } printf("\n"); //打印分隔行 if(i<row-1) for (j = 0; j < col; j++) { printf("---"); if (j < col - 1) printf("|"); } printf("\n"); }} Player(char board[ROW][COL], int row, int col){ while (1) { int x = 0; int y = 0; printf("请输入你的棋子坐标（如第一行第一列为1 1）：\n"); scanf("%d%d", &x, &y); if (x <= row && x >= 1 && y <= col && y >= 1) { if (board[x - 1][y - 1] == ' ') { board[x - 1][y - 1] = '*'; break; } else { printf("该处已有棋子，请重新输入\n"); continue; } } else printf("坐标范围错误,请重新输入"); }} Computer(char board[ROW][COL], int row, int col) { int x = 0; int y = 0; while (1) { x = rand() % ROW; y = rand() % COL; if (board[x][y] == ' ') { board[x][y] = '#'; break; } } } int IsFull(char board[ROW][COL], int row, int col)//返回1表示棋盘已满，0表示棋盘没满 { int i, j; for (i = 0; i < row; i++) { for (j = 0; j < col; j++) if (board[i][j] == ' ') return 0; } return 1; } char Judge(char board[ROW][COL], int row,int col) { int i = 0; //行有三个相连的情况 for (i = 0; i < row; i++) { if (board[i][0] == board[i][1] && board[i][1]== board[i][2] && board[i][0] != ' ') return board[i][0]; } //列有三个相连的情况 for (i = 0; i < col; i++) { if (board[0][i] == board[1][i] && board[1][i]== board[2][i] && board[0][i] != ' ') return board[0][i]; } //对角线三个相连的情况 if (board[0][0] == board[1][1]&& board[1][1]==board[2][2]&&board[0][0]!=' ' || board[0][2] == board[1][1]&&board[1][1] == board[2][0]&&board[0][2] != ' ') return board[1][1]; //平局的情况（棋盘满了） if (IsFull( board , ROW,COL) ==1) { return 'E'; } return 'C'; } |
主函数部分
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#include "game.h"void menu(){ printf("***************************\n"); printf("***1.开始游戏 0.退出游戏***\n"); printf("***************************\n"); printf("请输入数字1或0:");}void game(){ char r; char board[ROW][COL] = { 0 }; //初始化棋盘（清空棋盘） Initboard(board, ROW, COL); //打印棋盘 Displayboard(board, ROW, COL); //人机对弈 while (1) { Player(board, ROW, COL); Displayboard(board, ROW, COL); r = Judge(board, ROW, COL); if (r != 'C') break; Computer(board, ROW, COL); Displayboard(board, ROW, COL); r = Judge(board, ROW, COL); if (r != 'C') break; } //判断输赢 if (r == '*') { printf("玩家赢\n"); } else if (r == '#') { printf("电脑赢\n"); } else if (r == 'E') { printf("平局\n"); }}int main(){ srand((unsigned int)time(NULL)); int input = 0; do { menu(); scanf("%d", &input); switch (input) { case 1: printf("开始游戏\n"); game(); break; case 0: printf("退出游戏\n"); break; default: printf("请输入正确的选项\n"); break; } } while (input); printf("游戏结束！"); return 0;} |
以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持服务器之家。
原文链接：https://blog.csdn.net/Wyf_Fj/article/details/114210521
